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artcher [175]
3 years ago
15

Which are base units used in the metric system? Check all that apply.

Physics
2 answers:
Anestetic [448]3 years ago
8 0

Quarts - X

<h3>Liters - √</h3><h3>Grams - √</h3>

Degrees Fahrenheit - X

<h3>Degrees Celsius - √</h3>

Pints - X

I've tried my best with this, sorry if any are wrong.

Hope this helps,

Davinia.

Shtirlitz [24]3 years ago
7 0

Liters

Grams

Degrees Celsius

The other answer choices are from the imperial system

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A 49-year-old female was referred for mammography, but she is very apprehensive after reading about the risk of ionizing radiati
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Answer:

Mammography is the process in which low energy radiations are used to diagnose and screening. The purpose of this process is the early detection of the breast cancer. These low energy radiations may have some risks like damaging and burning of cells.  

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In this way radiographer should handle the situation.

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4 years ago
A frictionless pulley used to lift 8000N of concrete. What is the minimum effort required to raise the block
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3 0
3 years ago
Can anyone solve these for my by using unit vectors? Can you also please show your work
Oxana [17]

4. The Coyote has an initial position vector of \vec r_0=(15.5\,\mathrm m)\,\vec\jmath.

4a. The Coyote has an initial velocity vector of \vec v_0=\left(3.5\,\frac{\mathrm m}{\mathrm s}\right)\,\vec\imath. His position at time t is given by the vector

\vec r=\vec r_0+\vec v_0t+\dfrac12\vec at^2

where \vec a is the Coyote's acceleration vector at time t. He experiences acceleration only in the downward direction because of gravity, and in particular \vec a=-g\,\vec\jmath where g=9.80\,\frac{\mathrm m}{\mathrm s^2}. Splitting up the position vector into components, we have \vec r=r_x\,\vec\imath+r_y\,\vec\jmath with

r_x=\left(3.5\,\dfrac{\mathrm m}{\mathrm s}\right)t

r_y=15.5\,\mathrm m-\dfrac g2t^2

The Coyote hits the ground when r_y=0:

15.5\,\mathrm m-\dfrac g2t^2=0\implies t=1.8\,\mathrm s

4b. Here we evaluate r_x at the time found in (4a).

r_x=\left(3.5\,\dfrac{\mathrm m}{\mathrm s}\right)(1.8\,\mathrm s)=6.3\,\mathrm m

5. The shell has initial position vector \vec r_0=(1.52\,\mathrm m)\,\vec\jmath, and we're told that after some time the bullet (now separated from the shell) has a position of \vec r=(3500\,\mathrm m)\,\vec\imath.

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r_y=1.52\,\mathrm m-\dfrac g2t^2

We find the shell hits the ground at

1.52\,\mathrm m-\dfrac g2t^2=0\implies t=0.56\,\mathrm s

5b. The horizontal component of the bullet's position vector is

r_x=v_0t

where v_0 is the muzzle velocity of the bullet. It traveled 3500 m in the time it took the shell to fall to the ground, so we can solve for v_0:

3500\,\mathrm m=v_0(0.56\,\mathrm s)\implies v_0=6300\,\dfrac{\mathrm m}{\mathrm s}

5 0
4 years ago
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Lina20 [59]

Answer:

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Explanation:

There are 100 cm in 1 m. To convert from m to cm, multiply by 100.

6.6 \times 100 = 660

There are 660 cm in 1 m.

6 0
3 years ago
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