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Ilia_Sergeevich [38]
3 years ago
8

HELLPPPPPPP FASTTTTBDJEJDJDJSJJWJWJW

Physics
1 answer:
drek231 [11]3 years ago
6 0
I think they remain the same, i’m sorry bro i tried
You might be interested in
The sun emits energy in the form of electromagnetic waves produced by nuclear reactions deep in the sun's interior. Assume that
tatiyna

Answer:

I = W / 4π R_{s}²,   P = W / 2π c R_{s}², Io /I_{earth} = 10⁴  

Explanation:

The intensity is defined as the ratio between the emitted power and the area of ​​the spherical surface

               I = P / A

Since the emitted power is constant and has a value of W for this case, let's look for the area of ​​the sphere on the surface of the sun

             A = 4π R_{s}²

             I = W / 4π R_{s}²

.- The radiation pressure for total absorption is

             P = S / c

Where S is the Pointer vector that is equal to the intensity

Let's replace

             P = W / 2π c R_{s}²

.- We repeat for r = R_{s}/2

              I₂ = W / 4π (R_{s}/ 2)²

              I₂ = 4 W / 4π R_{s}²

              I₂ = 4 Io

              I₀ = W / 4piRs2

    We calculate the radiation pressure

             P₂ = I₂ / c

             P₂ = 4 I₀ / c

             P₂ = 4 (W / 4pi c Rs2)

.- the relationship between these magnitudes is

            I₂ / I₀ = 4

            P₂ / P₀ = 4

Let's calculate the intensity on the surface where the Earth is

            r = 1.50 10¹¹ m

           I_{earth} = W / 4π r²

           Io / I_{earth}   = r² /R_{s}²

          Io /I_{earth}  = (1.5 10¹¹ / 6.96 10⁸) 2

          Io /I_{earth} = 4.6 10⁴

          Io /I_{earth} = 10⁴

4 0
4 years ago
A runner drank a lot of water during a race. What is the expected path of the extra filtered water molecules?
Naddika [18.5K]

Answer:

Afferent arteriole, glomerulus, nephron tubule, collecting duct

Explanation:

Blood enters the kidney through the renal artery, a thick branch from the descending aorta. In the hilum, it is divided into several branches that are distributed through the lobes of the kidney and are branching forming numerous afferent arterioles that form the glomerular clew. It is precisely the walls of these capillaries that act as ultrafilters, allowing small particles to pass through.

Blood that flows through the <u>afferent arteriole</u> circulates through the capillary vessels of the kidney (the true capillaries that provide the kidney with oxygen and nutrients necessary for its function). These capillaries are grouped together to form the renal vein which, in turn, pours into the inferior vena cava.

Given the function of the kidneys to eliminate waste products through urine, it is not surprising that these organs are the ones that receive the most blood per gram of weight. One way to express renal blood flow is by considering the renal fraction or fraction of cardiac output that passes through the kidneys.

The regulation of blood flow in the glomeruli is achieved by three formations: the polar bearing, the Goormaghtigh cells and the dense macula. The polar bearing consists of a thickening of the afferent arteriole wall before it enters the <u>renal glomerulus</u>. The arteriole loses its elastic membrane, the endothelium becomes discontinuous and the middle tunic is arranged in two layers, formed by secretory cells: these secretory cells produce Angiotensin and Erythropoietin.

Goormaghtigh cells are arranged at an angle between afferent and effector arterioles and meet in small columns. They are closely related to polar bearing cells. Between both formations is the dense macula (or Zimmerman's dense macula) that is in contact with the distal tubule and afferent arteriole just before it penetrates the glomerulus. These three formations, polar bearing, Goormaghtigh cells and dense macula form the juxtaglomerular apparatus that regulates the blood flow in the glomerulus.

<u>Nephrons</u> regulate water and soluble matter (especially Electrolytes) in the body, by first filtering the blood under pressure, and then reabsorbing some necessary fluid and molecules back into the blood while secreting other unnecessary molecules.

The reabsorption and secretion are achieved with the mechanisms of Cotransporte and Contratransporte established in the nephrons and associated collection ducts. Blood filtration occurs in the glomerulus, a capping of capillaries that is inside a Bowman's capsule.

Liquid flows from the nephron in the <u>collecting duct</u> system. This segment of the nephron is crucial to the process of water conservation by the body. In the presence of the antidiuretic hormone (ADH; also called vasopressin), these ducts become water permeable and facilitate their reabsorption, thus concentrating the urine and reducing its volume. Conversely, when the body must remove excess water, for example after drinking excess fluid, ADH production is decreased and the collecting tubule becomes less permeable to water, making the urine diluted and abundant.

6 0
3 years ago
2)
ludmilkaskok [199]
B).  A <span>car that rounds a curve at a constant speed is accelerating.

</span><span>D).  A car that is set to a constant speed of 60 miles per hour is
accelerating IF the road ever curves. </span><span>

</span>
3 0
3 years ago
A force does work on an object if a component of the force is
IrinaK [193]

Answer:

A force does work on an object if a component of the force is parallel to the displacement of the object.

Explanation:

Work, a measurement of energy is said to be done when a force applied to an object results in the movement of that object to a certain distance and direction. Force is the act of push or pulls occurs on an object as a result of the interaction between that object with another one and displacement is the distance and direction covered by that object as a result of the force applied on it.

The work done (W) by a constant force (F) is equal to the product of the force in the direction of displacement of the object and the distance (d) moved by the object i.e., W = F * d.

The angle between the displacement and the force is θ, then the work done, W = Fd cos θ  ........ (1)

Positive work - Force acts in the same direction with respect to the displacement of the object. Here, θ is zero, so cos θ i.e., cos 0 is 1. Therefore, from the equation (1), W = Fd (i.e., work done by the force is positive).

Negative work - Force acts in the opposite direction with respect to the displacement of the object.  Here, θ is 180°, so cos θ i.e., cos 180° is -1. Therefore, from the equation (1), W = -Fd (i.e., work done by the force is negative).

If a force is applied to an object and it does not move, then the work done is zero i.e., W = F * 0 = 0. Also, if the force and displacement are at right angle to each other, then θ is 90°. Therefore, from the equation (1), W = 0 since cos 90° is zero.

7 0
4 years ago
How would you define an ocean current?
Kryger [21]

Answer:

i would describe an ocean current like a pull of the water

Explanation:

water

4 0
2 years ago
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