Explanation:
It is given that,
Distance between wires, d = 3.5 mm = 0.0035 m
Power of light bulb, P = 100 W
Potential difference, V = 120 V
(a) We need to find the force per unit length each wire of the cord exert on the other. It is given by :
Power, P = V × I
This gives, 
(b) Since, the two wires carry equal currents in opposite directions. So, teh force is repulsive.
(c) This force is negligible.
Hence, this is the required solution.
Answer:
2.55 m
Explanation:
Elastic energy = gravitational energy
½ kx² = mgh
h = kx² / (2mg)
h = (200 N/m) (0.05 m)² / (2 × 0.010 kg × 9.8 m/s²)
h = 2.55 m
<span>Answer:
Total kinetic energy at the bottom = 0.5(1+0.4) mv^2 = mgh
V^2 = 7*9.8/0.7
V = 9.9m/s
ω = V/r = 9.9/1.7 = 5.8rad/s
Answer c. 5.8 rad/s</span>
T o a stationary observer, a man jogs east at 2.5 m/s and a woman jogs west at 1.5 m/s. from the woman's frame of reference, what is the man's velocity? it is 4m/s east
