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Varvara68 [4.7K]
3 years ago
6

hey can anyone pls help me in dis! Complete the table below by exploring the “Solid, Liquid, Gas” tab in the simulation. Test yo

ur predictions and record your observations by recording the temperature and illustrations of each substance in the three states of matter.

Physics
1 answer:
bazaltina [42]3 years ago
4 0

Answer:

✍️Argon:

†Observation:

»» Solid:

★ Temperature: 43 Kelvin.

★ Illustration: Particles are in one position not moving.

»» Liquid:

★ Temperature: 86 Kelvin

★ Illustration: Particles are still compacted but slightly moving.

»» Gas:

★ Temperature: 189 Kelvin

★ Illustration: Particles are moving slowly around each other.

Explanation:

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if Xc = 7,500 and the resistance is 10,000 in a series RC circuit , what is the impedance of the circuit?
mr_godi [17]

Answer:

The impedance of the circuit = 12500 Ω

Explanation:

<em>Impedance:</em> This is the overall opposition to the flow of current in an a.c circuit by any two or all of the three circuit elements.(R, L, C) is called <em>impedance.</em>

<em>The  S.I unit of Impedance is Ohms. (Ω), It can be represented mathematically as</em>

Z = √(Xc² + R²).................... Equation 1

Where Z = impedance, Xc = reactance of the capacitor, R = resistance of the  resistor.

<em>Given: Xc = 7500 Ω, R = 10000 Ω</em>

<em>Substituting these values into equation 1,</em>

<em>Z = √(7500² + 10000²)</em>

<em>Z = √(56250000 + 100000000)</em>

<em>Z = √(156250000)</em>

Z =12500 Ω

Therefore, The impedance of the circuit = 12500 Ω

3 0
3 years ago
Read 2 more answers
An initially uncharged 3.47-μF capacitor and a 6.43-kΩ resistor are connected in series to a 1.50-V battery that has negligible
harkovskaia [24]

Answer: a) io=233.28 A ( initial current); b) τ=R*C= 22.31 ms; c) 81.7 ms

Explanation:  In order to explain this problem we have to use, the formule for the variation of the current in a RC circuit:

I(t)=io*Exp(-t/τ)

and also we consider that io=V/R=(1.5/6.43*10^3)

=233.28 A

then the time constant for the RC circuit is τ=R*C=6.43*10^3*3.47*10^-6

=22.31 ms

Finally the time to reduce the current to 2.57% of its initial value is obtained from:

I(t)=io*Exp(-t/τ)  for I(t)/io=0.0257=Exp(-t/τ) then

ln(0.0257)*τ =-t

t=-ln(0.0257)*τ=81.68 ms

3 0
3 years ago
Which one has more thermal energy?
Digiron [165]

Answer:

a bathtub full of warm water

Explanation:

Even though the water in a filled bathtub may be at the same temperature as water in a teacup, the water in the bathtub has more thermal energy because it contains a greater number of water molecules.

8 0
3 years ago
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A 260-kg glider is being pulled by a 1,940-kg jet along a horizontal runway with an acceleration of a= 2.20 m/s^2 to the right.
lisov135 [29]

Answer:

a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

Explanation:

a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:

Jet

\Sigma F = F - T = m_{J}\cdot a (1)

Glider

\Sigma F = T = m_{G}\cdot a (2)

Where:

F - Thrust of jet engines, measured in newtons.

T - Tension in the cable connecting the jet and glider, measured in newtons.

m_{G}, m_{J} - Masses of the glider and the jet, measured in kilograms.

a - Acceleration of the glider-jet system, measured in meters per square second.

If we know that m_{G} = 260\,kg, m_{J} = 1,940\,kg and a = 2.20\,\frac{m}{s^{2}}, then the solution of this system of equations:

By (2):

T = (260\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

T = 572\,N

By (1):

F = T+m_{J}\cdot a

F = 572\,N+(1,940\,kg)\cdot \left(2.20\,\frac{m}{s^{2}} \right)

F = 4840\,N

The magnitude of the thrust provided by the jet's engines is 4840 newtons.

b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.

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3 years ago
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The answer will be b
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