<span>If the refrigerator weights 1365 and you are not exerting any vertical force on it, then the normal force is also 1365N. so Fn=1365
Fsf = Static frictional force = (coefficient of static friction) * (Normal force)
So the least for you could exert to move it is equal to the Fsf.
Fsf = (0.49)(1365N)</span><span>
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It should be S since S stands for students. Giving the team with more members the upper hand. Hope this helps.
Answer:
Explanation:
Let the velocity of deuteron be v then force on it in magnetic field
Bqv , B is magnetic field and q is charge on deuteron . This force will provide centripetal force for circular path so
mv² / r = Bqv m is mass of deuteron and r is radius of circular path
v = Bqr / m
(.5 x 1.6 x 10⁻¹⁹ x 55.6 x 10⁻² )/ 3.34 x 10⁻²⁷
= 13.31 x 10⁶ m /s
Then the force of gravity between them would be quadrupled and so on but the gravitational force is inversely proportional to the square of the separation distance between the two interacting objects which makes more separation distance will result in weaker gravitational forces
Answer:
amount of work done, W = 549.36 kJ
Given:
mass of a car engine, m = 2500 kg
initial velocity, u = 45 mph
final velocity, v = 65 mph
1 mile = 1609
Solution:
We know that 1 hour = 3600 s
Now, velocities in m/s are given as:
u = 45 mph = 
= 20.11 m/s
v = 65 mph = 
= 29.05 m/s
Now, the amount of work done, W is given by the change in kinetic energy of the car and is given by:
W = 
W = 
W = 
W = 549.36 kJ
