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olga_2 [115]
3 years ago
12

Project: Modeling Energy Changes

Chemistry
1 answer:
ExtremeBDS [4]3 years ago
7 0

Answer:

A Chemical reaction involves changes in energy in the form of absorbtion and release of heat due to the formation and breakdown of chemical bonds. A chemical reaction is categoried as endothermic reaction in which heat energy is take in or absorbed and exothermic reaction in which energy is released.

<u>A model can be created by following below details:</u>

  • Take a beaker and put 10 milliliters of vinegar in it.
  • Place a thermometer in the beaker and measure the initial temperature.
  • Then add half teaspoon of baking soda, that results into decreasing in the temperature.

So, the decrease in temperature shows it is an endothermic reaction in which heat energy is absorbed.

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Three elements are represented by the letters A, B, and C. the three elements have the same number of valence electrons. Element
AfilCa [17]
Answer:
A- beryllium
B- calcium
C- magnesium

Explanation
NOTE: all element in group 2 have 2 balance electrons

First let’s start with B- number of electrons= number of protons which is equal to the atomic number. therefore, the answer is calcium as it’s atomic number is 20

C- magnesium will have three energy levels considering it has 12 electrons (2,8,2).

A- beryllium is the lightest one in group 2 as it has the atomic mass of 9.0122.
3 0
3 years ago
Given that Kp = 3.5 x 10-4 for the reaction 2 CO(g) &lt;=&gt; C(graphite) + CO2(g), what is the partial pressure of CO2(g) at eq
spin [16.1K]

<u>Answer:</u> The partial pressure of carbon dioxide at equilibrium is 0.0056 atm

<u>Explanation:</u>

The given chemical equation follows:

                     2CO(g)\rightleftharpoons C\text{ (graphite)}+CO_2(g)

<u>Initial:</u>             4.00

<u>At eqllm:</u>       4.00-2x        x                 x

The expression of K_p for above reaction follows:

K_p=\frac{p_{CO_2}}{(p_{CO})^2}

The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.

We are given:

K_p=3.5\times 10^{-4}

Putting values in above expression, we get:

3.5\times 10^{-4}=\frac{x}{(4-2x)^2}\\\\x=0.0056,718.28

Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure

Partial pressure of CO_2 = 0.0056 atm

Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm

4 0
3 years ago
Uma indústria de confecção de placas de alumínio deseja transportar 100 placas de alumínio para um cliente. Considerando que o v
Bogdan [553]
Questions:

The questions or computes to do are:

<span>a- a massa, em kg, de cada placa de alumínio;

b- a quantidade mínima de viagens necessárias para que apenas um veículo de transporte entregue o material solicitado ao cliente.

Dado: densidade do alumínio = 2,7 g/cm3

Answer:

a) mass in kg of every aluminum plate

Dimensions of every aluminum plate: </span>
<span>2 M X 50 Cm X 2cm

Volume: 200 cm * 50 cm * 2 cm = 20,000 cm^3

Mass:

density = mass / volume => mass = density * volume = 2.7 g/cm^3 * 20,000 cm^3 = 54,000 g = 54 kg.

Answer: the mass of everyplate of aluminum is 54 kg.

b) number of travels required for one truck deliver all the material:

number of travels = amount requested / amount that a truck can deliver in one travel.

amount requested: 100 plates

mass of 100 plates = 100 plates * 54 kg / plate = 5,400 kg

limit of transport per travel: 3 tons = 3,000 kg

number of travels = 5,400 kg / 3,000 kg/travel = 1.8 travels => 2 travels.

Answer: at least 2 travels.
</span>
8 0
3 years ago
Help me as quickly as possible
Flura [38]

Answer: 6. Radiation

7. weather

8. Heat

9. Climate

Explanation:

6 0
3 years ago
Help me! :&gt; i need help badlyyy
Alexxandr [17]

Answer:

Explanation:

s

3 0
3 years ago
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