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Paladinen [302]
3 years ago
11

What is energy state

Physics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
Answer: a quantum mechanic system
Hope this helps
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When two objects collide their momentum after the collision is explained by what
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The statement to every reacting there is, there is a opposite and same reacting. 
hope it helps
8 0
3 years ago
A tissue sample at 275 K is submerged in 2 kg of liquid nitrogen at 70 K for cryopreservation. The final temperature of the nitr
kirill115 [55]

Answer:

The heat capacity of a sample is 37.7 J/K.

Explanation:

Given that,

Submerged temperature of tissue sample = 275 K

Mass of liquid nitrogen= 2 kg

Temperature = 70 K

Final temperature = 75 K

We need to calculate the heat

Using formula of heat

Q=mc(T_{f}-T_{i})

Put the value into the formula

Q=2\times1.039\times10^{3}\times(75-70)

Q=10390\ J

We need to calculate the heat capacity of a sample

Using formula of heat capacity

\Delta S=\dfrac{Q}{T}

Put the value into the formula

\Delta S=\dfrac{10390}{275}

\Delta S=37.7\ J/K

Hence, The heat capacity of a sample is 37.7 J/K.

7 0
3 years ago
Read 2 more answers
How do materials, such as nutrients and waste, pass through the cell membrane?
Aleks04 [339]
Think of the cell membrane as a net and the nutrients are the perfect fit to fall through it. Where the waste is not the right size and will not fit through the holes of the net.
4 0
3 years ago
Type your answer...
ArbitrLikvidat [17]

Answer:

50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken

3 0
3 years ago
One string of a certain musical instrument is 70.0 cm long and has a mass of 8.79 g . It is being played in a room where the spe
Svetach [21]

To solve this problem we will apply the concepts of linear mass density, and the expression of the wavelength with which we can find the frequency of the string. With these values it will be possible to find the voltage value. Later we will apply concepts related to harmonic waves in order to find the fundamental frequency.

The linear mass density is given as,

\mu = \frac{m}{l}

\mu = \frac{8.79*10^{-3}}{70*10^{-2}}

\mu = 0.01255kg/m

The expression for the wavelength of the standing wave for the second overtone is

\lambda = \frac{2}{3} l

Replacing we have

\lambda = \frac{2}{3} (70*10^{-2})

\lambda = 0.466m

The frequency of the sound wave is

f_s = \frac{v}{\lambda_s}

f_s = \frac{344}{0.768}

f_s = 448Hz

Now the velocity of the wave would be

v = f_s \lambda

v = (448)(0.466)

v = 208.768m/s

The expression that relates the velocity of the wave, tension on the string and linear mass density is

v = \sqrt{\frac{T}{\mu}}

v^2 = \frac{T}{\mu}

T= \mu v^2

T = (0.01255kg/m)(208.768m/s)^2

T = 547N

The tension in the string is 547N

PART B) The relation between the fundamental frequency and the n^{th} harmonic frequency is

f_n = nf_1

Overtone is the resonant frequency above the fundamental frequency. The second overtone is the second resonant frequency after the fundamental frequency. Therefore

n=3

Then,

f_3 = 3f_1

Rearranging to find the fundamental frequency

f_1 = \frac{f_3}{3}

f_1 = \frac{448Hz}{3}

f_1 = 149.9Hz

7 0
3 years ago
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