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OleMash [197]
3 years ago
14

The law of repulsion by Coulomb agrees with: Newton's law of universal gravitation Newton's laws of motion the findings of Gilbe

rt the direct-square law
Physics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

F=\dfrac{kq_1q_2}{r^2}...............(1)

Where

F is the force

k is the electrostatic constant

q_1\ and\ q_2 are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

F=\dfrac{Gm_1m_2}{r^2}..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

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__________ is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.
7nadin3 [17]

Answer: Spina bifida

Explanation:

Spina bifida is a developmental defect in which a portion of the spinal cord protrudes outside the vertebrae.

Spina bifida is a birth defect that occurs when there is improper formation of the spine and spinal cord. It's a type of neural tube defect. The structure in a developing embryo that eventually becomes the baby's brain, spinal cord and the tissues that enclose them is the neutral tube.

3 0
3 years ago
A steel cable has a cross-sectional area 4.49 × 10^-3 m^2 and is kept under a tension of 2.96 × 10^4 N. The density of steel is
Lemur [1.5K]

Answer:

The transverse wave will travel with a speed of 25.5 m/s along the cable.

Explanation:

let T = 2.96×10^4 N be the tension in in the steel cable, ρ  = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.

then, if V is the volume of the cable:

ρ = m/V

m = ρ×V

but V = A×L , where L is the length of the cable.

m = ρ×(A×L)

m/L = ρ×A

then the speed of the wave in the cable is given by:

v = √(T×L/m)

  = √(T/A×ρ)

  = √[2.96×10^4/(4.49×10^-3×7860)]

  = 25.5 m/s

Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.

7 0
3 years ago
Simple Pendulum: A 34-kg child on an 18-kg swing set swings back and forth through small angles. If the length of the very light
SIZIF [17.4K]

Answer:

The correct answer is "4.443 sec".

Explanation:

Given:

Mass of child,

= 34 kg

Mass of swing,

= 18 kg

Length,

= 4.9 m

The time period of pendulum will be:

T = 2 \pi \sqrt{4g}

  = 2 \pi \sqrt{\frac{4.9}{9.8} }

  = 4.443 \ sec  

5 0
3 years ago
Read 2 more answers
As you approach a roundabout, you should __________________.
motikmotik
The answer should be B
8 0
3 years ago
Read 2 more answers
The speed of a car during a trip is represented in the graph. Compare distance and displacement at four hours into the trip.
mezya [45]

Answer:

The answer to your question is: D.

Explanation:

Distance refers to the amount of space between two points, it is a scalar quantity.

Displacement refers to the space between two points, measure from the minimum path linking them, it is a vector quantity.

I'm not agree with these answers, because the total distance  is approximately 500km.

A) The distance traveled is 300 km.  This answer is not correct.

B) Distance is 300 km and displacement is 0 km.  This answer is not correct because the displacement is also 500 km.

C) Distance is 300 km/hour and displacement is 300 km. 300 km/h is a measure of speed not of distance, this option is wrong.

D) Both distance traveled and displacement are 300 km. I think this is the correct answer because distance and displacement measure the same. but I think both measure 500 km.

7 0
3 years ago
Read 2 more answers
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