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oee [108]
3 years ago
13

If a 20 N force acts on a 10 kg object for 0.5 seconds. If the object starts at rest, what would it’s new p (momentum) and v (ve

locity) be?
Physics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

p=10\:\text{kgm/s}},\\v_f=1\:\text{m/s}

Explanation:

From Newton's 2nd Law, we have \Sigma F=ma. We can use this to find the acceleration of object after 20 N (force) is applied to the 10 kg object.

Substituting given values, we have:

\Sigma F=ma, \\20=10a,\\a=\frac{20}{10}=2\:\mathrm{m/s^2}

Now that we have acceleration, we can find the final velocity of object (after 0.5 seconds) using the following kinematics equation:

v_f=v_i+at, where v_f is final velocity, v_i is initial velocity, a is acceleration, and t is time.

Solving for final velocity:

v_f=0+2\cdot 0.5,\\v_f=\boxed{1\:\text{m/s}}

The momentum of an object is given as p=mv. Since we've found the final velocity and mass stays constant, we have:

p=10\cdot 1=\boxed{10\:\text{kgm/s}}

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Answer:

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Explanation:

Given:

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where,

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thus, we have

C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})

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or

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taking log both sides, we get

ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})

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t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}

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