Answer:
300K
Explanation:
Given pressure of the system decreased by 10 times which means 
Given the volume of the system increased by 5 times which means 
Given final temperature 
Let the initial temperature be 
We know that PV=nRT
As n and R are constant 
T1=300K
<span>number Moles of C = 54.5 g / 12.011 = 4.54
number Moles of H = 9.10 / 1.008 = 9.02
number Moles of O = 36.4 / 16 = 2.28
if we want to divide by the smallest number
4.54 / 2.28 = 2 => C
9.02 / 2.28 = 4 => H
2.28 / 2.28 = 1 => O
Empirical formula will be = C2H4O</span>
Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
Answer:
sodium hydroxide and hydrochloric acid is the reactants
Answer:
Cations are positively charged atoms and hence we need to make the atom positively charged in order to get a cation
We know that an atom is neutral as a whole, so we have equal number of electrons and protons
since we cannot mess with the number of protons in an atom, we have to do it by altering the number of electrons
If we reduce the amount of electrons in an atom, the net charge will be positive and hence a cation will be formed
