Answer:
Vapor pressure of solution is 78.2 Torr
Explanation:
This is solved by vapor pressure lowering:
ΔP = P° . Xm . i
Vapor pressure of pure solvent (P°) - vapor pressure of solution = P° . Xm . i
NaCl → Na⁺ + Cl⁻ i = 2
Let's determine the Xm (mole fraction) These are the moles of solute / total moles.
Total moles = moles of solvent + moles of solute
Total moles = 0.897 mol + 0.182 mol → 1.079 mol
0.182 / 1.079 = 0.168
Now we replace on the main formula:
118.1° Torr - P' = 118.1° Torr . 0.168 . 2
P' = - (118.1° Torr . 0.168 . 2 - 118.1 Torr)
P' = 78.2 Torr
47/3 which could be simplified to 15.6
If temperature were to double the pressure would likewise double. Increased temperature would increase the energy of the molecules and the number of collisions would also increase causing the increase in pressure.
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