The time needed for the hammer to reach the surface of the Earth is 3.54 s.
<h3>
Time of motion of the hammer</h3>
The time of motion is calculated as follows;
t = √(2h/g)
where;
- h is height of fall
- g is acceleration due to gravity
t = √(2 x 10 / 1.6)
t = 3.54 s
Thus, the time needed for the hammer to reach the surface of the Earth is 3.54 s.
Learn more about time of motion here: brainly.com/question/2364404
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Answer:
4.96×10¯¹⁰ N
Explanation:
The following data were obtained from the question:
Mass 1 (M1) = 300 Kg
Mass 2 (M2) = 300 Kg
Separating distance (r) = 110 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Gravitational force (F) =?
The gravitational force between the two goal posts can be obtained as follow:
F = GM1M2 / r²
F = 6.67×10¯¹¹ × 300 × 300 / 110²
F = 6.003×10¯⁶ / 12100
F = 4.96×10¯¹⁰ N
Therefore the gravitational force between the two goal posts is 4.96×10¯¹⁰ N
Answer:
140°
Explanation:
The law of reflection states that the angle of redlection equals to the angle of incidence.
When light rays hit surface at 20°, they also leave the surface at the same angle
Since the whole surface has 180° then subtracting these two angles from total angle gives the the angle between the incident and reflected rays.
180°-20°-20°=140°
The angle of incidence and reflection are equal hence 140/2=70°
The question needed the angle between the incident and reflected rays which is already calculated as 140°
Answer:
5.15348 Beats/s
4.55 mm
Explanation:
= Velocity of sound = 342 m/s
= Velocity of sound = 346 m/s
= First frequency = 440 Hz
Frequency is given by
Beat frequency is given by
Beat frequency is 5.15348 Hz
Wavelength is given by
Relation between length of the flute and wavelength is
At v = 346 m/s
Difference in length is
It extends to 4.55 mm
Answer:
Explanation:
a ) Direction of the magnetic field will be in positive x direction.
The direction of the vector E X B gives the direction of motion of wave.
b ) Magnitude of magnetic field is given by the relation
E₀ / B₀ = c , c is velocity of light
B₀ = E₀ / c
= 20 / (3 x 10⁸)
= 6.67 x 10⁻⁸ T
c ) Average power flowing per unit area by this wave is called Poynting vector
c ε₀E₀² , ε₀ = 8.85X10⁻¹²
= 3 X 10⁸ X 8.85 X 10⁻¹² X 20²
= 1.062 W m⁻²
