If 31.8 grams of LiCl are dissolved in 225 grams of water, what is the concentration of the solution in percent by mass?

erik [133]

Answer:

1) The correct step in the scientific method that Victor did is Construct a hypothesis.

2) Given mass and density, volume is calculated as mass divided by density.

Explanation:

1) Before doing the assay and make a graph with the results obtained, Victor should think what he wants to prove, so he should make a hypoythesis to test with the assay.

2) The formula of density is

density = mass/volume ⇒ density x volume = mass ⇒ volume = mass/density.

4 0

3 years ago

Read 2 more answers

A carbon skeleton is covalently bonded to both an amino group and a carboxyl group. When placed in water it ____

kotykmax [81]

Answer:

The correct option is: (D) would function as both an acid and a base

Explanation:

A carbon skeleton bonded to a amino group as well as a carboxyl group, will behave as an acid in basic medium and base in acidic medium. This is because the carboxyl group present in the compound will release a proton in basic medium and the amino group will accept a proton in the acidic medium.

Therefore, a carbon skeleton which is covalently bonded to a carboxyl and amino group will behave as both acid and base.

8 0

3 years ago

Provide at least three indicators of a chemical change that are present in burning a piece of paper.

Pie

Answer:

Some chemical indicators perceived while a piece of paper is burning are:

Production of an Odor: there is a smell of burnt paper

Change in Temperature: combustion is a highly exothermic reaction , so the temperature increase

Change in Color: paper changes to ashes as the burning process occurs

3 0

3 years ago

A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and

sammy [17]

Answer: The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

Explanation:

To calculate the molality of solution, we use the equation:

$Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(S_8)$ = 0.800 g

$M_{solute}$ = Molar mass of solute $(S-8)$ = 256.52 g/mol

$W_{solvent}$ = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

$\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m$

Calculation for freezing point of solution:

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

$\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

or,

$\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm$

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC$

Hence, the freezing point of solution is 16.5°C

Calculation for boiling point of solution:

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

or,

$\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm$

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

$K_f$ = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC$

Hence, the boiling point of solution is 118.2°C

5 0

3 years ago

Classify the type of this chemical reaction: C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)

sweet-ann [11.9K]

The given reaction is a combustion reaction, since a hydrocarbon is burning in presence of oxygen

8 0

3 years ago

Read 2 more answers