All categories

3 years ago

A free negative charge released in an electric field will

Physics

1 answer:

SashulF [63]3 years ago

5 0

Answer:

Will experience a force due to electric field.

Explanation:

When a free negative charge is released in an electric field it experiences a force due to the electric field in a direction opposite to the direction of the magnetic field.

According to Coulomb's law this force is mathematically given as:

$F=E.q$

and, electric field due to a charge is given as:

$E=\frac{1}{4\pi.\epsilon_0}.\frac{q}{r^2}$

where:

permittivity of free space $\epsilon_0=8.85\times 10^{-12}\ m^{-3}.kg^{-1}.s^4.A^2$

q = magnitude of charge

r = radial distance from the charge

You might be interested in

Graphs often permit scientists to make estimations for items when there is no data. Please select the best answer from the choic

Zinaida [17]

Answer:

no they don't but I think it's 8

3 0

2 years ago

A force F~ = Fx ˆı + Fy ˆ acts on a particle that

Hatshy [7]

Answer:

W = 46 J

Explanation:

We need to find the angle between the two vectors Force vector and displacement vector.

First we will find the angle α of the force vector

$tan\alpha =\frac{1}{8} \\\\\\alpha =7.125 deg\\$

Then we find the angle β of the displacement vector

$tan\beta=\frac{2}{6} \\\\beta = 18.43 deg\\$

With these two angles we can find the angle between the two vectors

∅ = α + β = 25.56 deg

The definition of work is given by the expression

$W=F*d*cos (theta)$

The absolute value of F will be:

$F=\sqrt{8^{2}+1^{2} } \\F= 8.06 N$

The absolute value of d will be:

$d=\sqrt{(6 )^{2}+(2)^{2} } \\d= 6.32m\\$

Now we have:

$W=8.06*6.32*cos(25.56)\\W=46 J$

4 0

3 years ago

NEED HELP ASAP WILL MARK BRAINLIEST.

-Dominant- [34]

G is the answer for apex vs / Chehhhh

3 0

2 years ago

How can recycling impact the environment?

Diano4ka-milaya [45]

Answer:

a is a good answer

Explanation:

because most items whether clothes or things we eat with, are made with something natural and recycled

6 0

3 years ago

What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport

ad-work [718]

Answer: $1.13(10)^{3} Pa$

Explanation:

This problem can be solved by the following equation:

$\Delta P=\frac{8 \eta L Q}{\pi r^{4}}$

Where:

$\Delta P$ is the pressure difference between the two ends of the pipe

$\eta=0.20 Pa.s$ is the viscosity of oil

$L=2.6 km=2600 m$ is the length of the pipe

$Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s}$ is the Rate of flow of the fluid

$d=36 cm=0.36 m$ is the diameter of the pipe

$r=\frac{d}{2}=0.18 m$ is the radius of the pipe

Soving for $\Delta P$ :

$\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}$

Finally:

$\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa$

7 0

2 years ago