Why do animal cells not need central vacuoles? Help A.S.A.P! Please!

Physics

1 answer:

Tamiku [17]2 years ago

8 0

Answer:

This is because animals do not need to store as much water as plants.

Explanation:

Animals generally have smaller vacuoles than plants. Plants have large vacuoles that can occupy a large portion of their cell (up to 30 percent). The major function of the vacuole is to store water and maintain cell turgidity and pressure against the cell wall.

Animals on the other hand do not have a rigid cell wall, rather, they have a flexible cell membrane. As a result of this, they do not need to store water in vacuoles.

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Compare and contrast the average kinetic energy of 0.5 L of coffee at 34ÁC,

Andre45 [30]

Compared to coffee at room temperature, the molecules of the coffee at 34°C will be moving faster and colliding with one another more frequently.

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2 years ago

Which of these best describes the relationship between the incident ray, the reflected ray, and the normal for a curved mirror?(

lions [1.4K]

For a curved mirror, all points have the same normal and the angle of incidence is also equal to the angle of reflection.

According to the laws of reflection, the incident ray, reflected ray and normal all lie on the same plane. For a curved mirror, the normal remains the same at all points along the curved mirror.

Again, the angle made between the incident ray and the normal is the same as the angle made between the reflected ray and the normal. Therefore, the angle of reflection is equal to the angle of incidence.

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2 years ago

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (a) Calculate its ve

Gemiola [76]

Answer:

(a) v = 5.42m/s

(b) vo = 4.64m/s

(d) Δy = 5.11*10^-3m

Explanation:

(a) The velocity of the ball before it hits the floor is given by:

$v=\sqrt{2gh}$ (1)

g: gravitational acceleration = 9.8m/s^2

h: height where the ball falls down = 1.50m

$v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}$

The speed of the ball is 5.42m/s

(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

$h_{max}=\frac{v_o^2}{2g}$ (2)