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alexira [117]
4 years ago
6

A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars

combine.A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars combine. What is the magnitude of the final velocity of the combined cars?
Physics
1 answer:
VLD [36.1K]4 years ago
6 0
In order to compute the final velocity of the trains, we may apply the principle of conservation of momentum which is:
initial momentum = final momentum
m₁v₁ = m₂v₂

The final mass of the trains will be:
10,000 + 10,000 = 20,000 kg
Substituting the values into the equation:

10,000 * 3 = 20,000 * v
v = 1.5 m/s

The final velocity of the trains will be 1.5 m/s
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Alisiya [41]
The work done by the elephant to lift one log is the force multiplied by the height at which the log has been lifted:
W=Fh=250 N \cdot 5 m=1250 J
And so, the total work done to lift the 7 logs is 7 times the work done to lift each log:
W_t = 7 W=7 \cdot 1250 N=8750 J
5 0
3 years ago
Turn the ignition switch to start and release the key immediately or you could destroy the______________.
vredina [299]

Starter

Explanation:

Turn the ignition switch to start and release the key immediately or you could destroy the starter.

The car starter is used to cause ignition in the internal combustion engine in order to fire the piston and cause mechanical motion. The starter is used to start the cyclic process of the internal combustion engine.

  • Once the engine starts by igniting the starter, it is best to release it.
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Automobile brainly.com/question/2599962

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5 0
4 years ago
What is the speed of the animal from 0-20s? <br><br> 50 m/s<br> 0.4 m/s<br> 20 m/s<br> 2.5 m/s
Shkiper50 [21]

Answer:

2.5 m/s

Explanation:

The speed of the animal is given by the ratio between the distance travelled by the animal and the time elapsed:

v=\frac{d}{t}

where d is the distance travelled and t the time elapsed. Note that this quantity is also equal to the slope of the curve.

In the time interval 0-20 s, we have

d = 50 m - 0 m = 50 m

t = 20 s - 0 s = 20 s

So, the speed is

v=\frac{50 m}{20 s}=2.5 m/s

3 0
3 years ago
A woman of mass 50 kg is swimming with a velocity of 1.6 m/s. If she stops stroking and glides to a stop in the water, what is t
Snezhnost [94]

Answer:

Impulse of force = -80 Ns

Explanation:

<u>Given the following data;</u>

Mass = 50kg

Initial velocity = 1.6m/s

Since she glides to a stop, her final velocity equals to zero (0).

Now, we would find the change in velocity.

Change \; in \; velocity = final \; velocity - initial \; velocity

Substituting into the equation above;

Change in velocity = 0 - 1.6 = 1.6m/s

Impulse \; of \; force = mass * change \; in \; velocity

Substituting into the equation, we have;

Impulse \; of \; force = 50 * -1.6

<em>Impulse of force = -80 Ns</em>

<em>Therefore, the impulse of the force that stops her is -80 Newton-seconds and it has a negative value because it is working in an opposite direction, thus, bringing her to a stop. </em>

5 0
3 years ago
Suppose we take a 1 m long uniform bar and support it at the 33 cm mark. Hanging a 0.15 kg mass on the short end of the beam res
MakcuM [25]

Answer:

The mass of the beam is 0.074 kg

Explanation:

Given;

length of the uniform bar, = 1m = 100 cm

Set up this system with the given mass and support;

  0-----------------33cm-----------------------------------100cm

  ↓                     Δ                                             ↓      

0.15kg                                                              m

Where;

m is mass of the uniform bar

Apply the principle of moment to determine the value of "m"

sum of anticlockwise moment = sum of clockwise moment

 0.15kg(33 - 0) = m(100 - 33)

0.15(33) = m(67)

m = \frac{0.15kg(33 \ cm)}{67 \ cm}\\\\m = 0.074 \ kg

Therefore, the mass of the beam is 0.074 kg

8 0
3 years ago
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