Answer:
<em>0.25</em>
Explanation:
According to newtons law of motion
\sum F_x = ma
F_f = ma
nR = ma
nmg = ma
ng = a
n = a/g
g is the acceleration due to gravity
Given
a = 2.42m/s²
g = 9.8m/s²
Substitute into the formula;
n = 2.42/9.8
n = 0.25
<em>Hence the coefficient of kinetic friction is 0.25</em>
<em></em>
Answer:
<em>262.4 m/s</em>
<em></em>
Explanation:
The complete question is
If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.
The distance fallen s = 16t^2
The velocity v =
= 32t
If we substitute the values of t into the velocity v, we'll have
at t = 8 s, V1 = 32 x 8 = 256 m/s
at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s
Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = <em>262.4 m/s</em>
The circulation system for mammals is very complex