Answer:
Mass of C = 47.37g
Mass of H = 10.59g
Mass of O = 42.04g
The total mass of these elements is 100g, taking a proportion of their molar masses.
C = 47.37/12= 3.95
H = 10.59/1 = 10.59
O = 42.04/16= 2.63.
Dividing through with the smallest proportion which is 2.63
C=3.95/2.63 = 1.5
H =10.59/2.63 =4
O = 2.63/2.63= 1
Multiplying through by 2 to get a whole number.
C = 1.5x2 = 3
H= 4x2 = 8
O = 1x2= 2
The empirical formula is C3H6O2
(Empirical formula)n= molecular mass
(C3H8O2)n =228.276
(12x3 +8+16x2)n= 228.276
76n = 228.276
n = 228.276/76
n = 3
Molecular formula = Empirical formula
=(C3H8O2)3 = C9H24O6
The molecular formula is C9H24O6
Four significant figures would be B. Because 0's before the decimal are not important, but 0's after the decimal are.
An unscientific device for locating oil or minerals; a divining rod.
Molecular chemical equation:
K₂C₂O₄(aq)+Pb(OH)₂(aq) → 2KOH(aq) + PbC₂O₄<span>(s).
Ionic equation:
2K</span>⁺(aq) + C₂O₄²⁻(aq) + Pb²⁺(aq) + 2OH⁻(aq) → 2K⁺(aq) +2OH⁻(aq)+PbC₂O₄(s)
Net ionic eqation:
C₂O₄²⁻(aq) + Pb²⁺(aq) → PbC₂O₄(s).
s is solid, do not dissolve in water, potassiom hydroxide is trong base and dissolves in water.
Answer:
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.
Explanation:
Mass of sulfuric acid = 0.98 g
Moles of sulfuric acid = 
Mass of sodium hydroxide = 0.240 g
Moles of sodium hydroxide = 

According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid , then 0.0060 moles of sodium hydroxide will react with :
of sulfuric acid
As we can see that we have 0.010 moles of sulfuric acid but only 0.0030 moles of sulfuric acid will react which indicates that it is in excessive amount where as sodium hydroxide is in limiting amount.
So, amount of sodium sulfate to be formed will depend upon moles of sodium hydroxide.
According to reaction, 2 moles of sodium hydroxide gives with 1 mole of sodium sulfate , then 0.0060 moles of sodium hydroxide will give :
of sodium sulfate
Mass of 0.0030 moles of sodium sulfate :
0.0030 mol × 142 g/mol = 0.426 g ≈ 0.43 g
0.43 grams is the maximum mass of sodium sulfate that could be produced by the chemical reaction.