Robert Millikan's oil drop experiment proved that it determined the actual mass of the electron. Robert Millikan was a well known experimental physicist.
Answer:
Diffusion is faster at higher temperatures because the gas molecules have greater kinetic energy. Effusion refers to the movement of gas particles through a small hole. Graham's Law states that the effusion rate of a gas is inversely proportional to the square root of the mass of its particles
The structure that corresponds to the molecule name - 4-heptanol would be option A.
<h3>Structure of 4-heptanol</h3>
The name, 4-heptanol, indicates that there are 7 carbon atoms in the structure.
In addition, there is also an indication that there is a functional group on the 4th carbon - the alcohol functional group.
Option B has only 6 carbon atoms instead of 7. Option A, on the other hand, fulfills all the criteria.
Thus, A is the correct structure of 4-heptanol.
More on structure of compounds can be found here:brainly.com/question/8155254
#SPJ1
<u>Answer:</u> The concentration of nitrogen dioxide at equilibrium is 0.063 M
<u>Explanation:</u>
We are given:
Initial concentration of nitrogen dioxide = 0.0250 M
Initial concentration of dinitrogen tetraoxide = 0.0250 M
For the given chemical equation:
<u>Initial:</u> 0.025 0.025
<u>At eqllm:</u> 0.025-x 0.025+2x
The expression of 
for above equation follows:
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
We are given:
Putting values in above expression, we get:
Neglecting the negative value of 'x', because concentration cannot be negative
So, equilibrium concentration of nitrogen dioxide = (0.025 + 2x) = [0.025 + 2(0.019)] = 0.063 M
Hence, the concentration of nitrogen dioxide at equilibrium is 0.063 M
