20 ohms in parallel with 16 ohm= 8.89
20x16/20+16. Product over sum
A spring is originally 0.4m. When a 23N force is applied it stretches to a total of 0.7m. How far is the spring been extended? W
1 answer:
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20 ohms in parallel with 16 ohm= 8.89
20x16/20+16. Product over sum
Answer:
6.03 m
Explanation:
First of all, let's convert the angular velocity from revolutions per minute to radians per second:
The frictional force on the block ranges from zero to a maximum value of
In order for the block to remain stuck on the turntable, the frictional force must be equal to the centripetal force, so we can write:
where
m is the mass of the block
is the angular velocity
r is the distance of the block from the centre
is the coefficient of static friction
g = 9.8 m/s^2
Solving for r, we find:
The distance between the similar charges is 0.753 m. The electric force is the inverse of the square of the distance.
<h3>What is electric force?</h3>Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The given data in the problem is;
q₁,q₂ are the charges = 1.6 ×10⁻¹⁹ C
R is the distance
F is the electric force=2.0×10²⁴ N
The electric force is found as;
Hence, the distance between the similar charges is 0.753 m.
To learn more about the electric force, refer to the link;
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Answer:
Explanation:
As we know that
PV = nRT
here we have
so we have
T = 290 K
now we have
now the mass of gas is given as
now density of gas when its volume is increased to 3.3 L
so we will have