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3 years ago

What does frequency describe?

Physics

2 answers:

ddd [48]3 years ago

7 0

The whole definition of frequency is: <em>How often something happens. </em>

Especially referring to something that happens over and over and over and over.

One example is Choice-C: How often the particles of a medium vibrate.

"Frequency" comes from the word "frequent". That means "often", and "frequency" just means "often-ness" ... HOW often the thing happens.

Some other examples:

Frequency of jump-roping . . . maybe 60 per minute .

Frequency of rain . . . maybe 5 per month .

Frequency of an AM radio station . . . maybe 1 million waves per second.

(If it's something <u><em>per second</em></u>, then we call it "Hertz". That's not for the car rental company. It's for Heinrich Hertz, the German Physicist who was the first one to prove that electromagnetic waves exist. He sent radio waves all the way ACROSS HIS LABORATORY and detected them at the other side ( ! ), in 1887.)

Frequency of the wiggles in the sound wave coming out of a trumpet playing the note ' A ' . . . 440 Hertz.

Frequency of sunrise and the Chicago Tribune newspaper . . . 1 per day

Frequency of the cycle of Moon phases and an average human woman's ovulation cycle: 1 per 29.531 days, 1 per ~28 days .

Anarel [89]3 years ago

4 0

(C). How often the particles of a medium vibrate.

<h3>Further explanation</h3>

Let us analyze the answer choices one by one.

A: Distance from crest to crest or from trough to trough on a wave.

This statement represents the definition of wavelength. The distance between crest or between trough is the distance of one wave, that is the wavelength.

B: Depth of a wave.

The depth of a wave is the depth of influence of a water wave, which is about half the wavelength.

C: How often the particles of a medium vibrate.

Yes right, this statement describes frequency. The frequency of a wave refers to how often the particles of the medium vibrate when a wave passes through the medium.

D: Height of wave is the distance between two amplitudes.

Recall that the period and the frequency of any wave are inversely related.

$\boxed{ \ T = \frac{1}{f} \ } \rightarrow \boxed{ \ f = \frac{1}{T} \ }$

_ _ _ _ _ _ _ _ _ _

Definition:

Amplitude (A) = the maximum displacement from the mean position, in unit of meters (The SI measurement).
Period (T) = the time taken for one complete wave (The SI measurement: in second).
Frequency (f) = the number of oscillations completed per unit time, or the number of cycles per second (The SI measurement: in Hertz or Hz).
Wavelength (λ) = the shortest distance (in meters) along with the wave between two points that are moving exactly in step with one another. In other words, the wavelength is the distance traveled in one wave.
Wave speed (v) = the speed (in m/s) at which the wavefronts pass a stationary observer. The speed of the wave is the quotient of wavelength with the period or the product of wavelength with frequency.

$\boxed{ \ v = \frac{\lambda}{T} \ } \ \boxed{ \ v = \lambda f \ }$

<h3>Learn more</h3>

How are period and frequency related to each other? brainly.com/question/10239637
The characteristics of electromagnetic waves brainly.com/question/727976
Determine the shortest wavelength in electron transition brainly.com/question/4986277

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2 years ago

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1) 1.2 m/s

First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

$\omega_f = \omega_i + \alpha t$

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$\alpha = 0.895 rev/s^2$ is the angular acceleration

Substituting t = 0.200 s, we find

$\omega_f = 0.300 + (0.895)(0.200)=0.479 rev/s$

Let's now convert it into rad/s:

$\omega_f = 2\pi \cdot 0.479 rev/s=3.01 rad/s$

The distance of a point on the tip of the blade is equal to the radius of the blade, so half the diameter:

$r=\frac{0.800}{2}=0.400 m$

And so now we can find the tangential speed at t = 0.200 s:

$v=\omega_f r =(3.01)(0.400)=1.2 m/s$

2) $2.25 m/s^2$

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

$a_t = \alpha r$

where $\alpha$ is the angular acceleration.

First of all, we need to convert the angular acceleration into rad/s^2:

$\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2$

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$a=\frac{v^2}{r}$

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r is the distance from the centre of the circle

We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

$a=\frac{1.2^2}{0.400}=3.6 m/s^2$

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3 years ago

A coin and feather are dropped in a moon. what will fall earlier on ground.give reasons.if they are dropped in the earth,which o

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on the moon, they will fall at the time

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A coin and feather dropped in a moon experience the same acceleration due to gravity as small as 1.625 m/s², and because of the absence of air resistance both will fall at the same rate to the ground.

If the same coin and feather are dropped in the earth, they will experience the same acceleration due to gravity of 9.81 m/s² and because of the presence of air resistance, the heavier object (coin) will be pulled faster to the ground by gravity than the lighter object (feather).

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