Question

The water in an 8-m-diameter, 3-m-high above-ground swimming pool is to be emptied by unplugging a 3-cm-diameter, 25-m-long horizontal pipe attached to the bottom of the pool. Determine the maximum discharge rate of water through the pipe in liters per second.

Answer 1

Answer:

The maximum discharge rate of water is 4.6 L/s

Explanation:

Given data:

d=diameter=8 m

h=height=3 m

The mathematical expression for the theoritical velocity is:

$v_{th} =\sqrt{2gh} =\sqrt{2*9.8*3} =7.6681m/s$

The maximum discharge can be calculate by:

$Q=C_{d} Av_{th}$

Here

Cd=coefficient of discharge=0.855

$Q=0.855*\frac{\pi }{4} *d^{2} *vx_{th} =0.855*\frac{\pi }{4} *0.03^{2} *7.6681=0.0046m^{3} /s=4.6L/s$