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goldfiish [28.3K]
3 years ago
8

The total mass of an object can be assumed to be focused at one point, which is called its center of _______. A. force B. veloci

ty C. mass D. inertia
Physics
2 answers:
garri49 [273]3 years ago
7 0

Answer:

The answer is mass. C

Explanation

I just got this and it was Mass.

QveST [7]3 years ago
4 0
C.) <span>The total mass of an object can be assumed to be focused at one point, which is called its center of "Mass"

Hope this helps!</span>
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A hockey puck with a mass of 0.175 kg slides over the ice. The puck initially slides with a speed of 5.25 m/s, but it comes to a
Neko [114]

Answer:

1.70 J

Explanation:

The heat dissipated is the difference in the kinetic energies.

This is given by

E = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

v_i and v_f are the initial and final velocities.

With <em>m</em> = 0.175 kg,

E = \frac{1}{2}\times0.175(2.85^2 - 5.25^2) = -1.701\text{ J}

The negative sign appears because energy is lost.

7 0
3 years ago
5. What is the speed of a wave in a spring if it has a wavelength of 10 cm and a period of 0.2s
eimsori [14]

Explanation:

speed of wave

v = wavelength x frequency

since frequency is f = 1/Period then

v = wavelength : Period

v = 10 cm/ 0.2 s = 50 cm/s

v = 0.5 m/s

7 0
3 years ago
A shotputter throws the shot with an initial speed of 15.6 m/s at a 30.0 degree angle to the horizontal. Calculate the horizonta
vfiekz [6]
To calculate the horizontal distance traveled by the shot if it leaves the athlete's hand at a height of 2.20 above the ground we can get the root of the quad equation for time are t=-0.24 or t =1.84 taking the t = 1.84, so the equation will be:
x = 15.6cos(30) * 1.86, x = 24.79m
8 0
3 years ago
What is the drivers displacement at the end of the lap
NeX [460]

Answer:

The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.

Explanation:

4 0
3 years ago
The weight of a 630 g piece of ham is _____.
Pachacha [2.7K]
The weight of an object is given by:
F=mg
where
F is the weight
m is the mass of the object
g=9.81 m/s^2 is the gravitational acceleration

The piece of ham in this problem has a mass of
m=630 g = 0.63 kg
therefore its weight is
F=mg=(0.63 kg)(9.81 m/s^2)=6.18 N
8 0
3 years ago
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