The magnitude of velocity for this car is equal to 1.5 m/s.
<u>Given the following data:</u>
- Momentum of car = 3,000 kgm/s.
To calculate the magnitude of velocity for this car:
<h3>What is momentum?</h3>
In Science, momentum simply means a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by the formula;
Making velocity the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Velocity = 1.5 m/s.
Read more on momentum here: brainly.com/question/15517471
The density of sample is 5 g/cm3
Given:
volume of sample = 20 cm3
mass of sample = 100 grams
To Find:
density of sample
Solution: Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick. It is defined as mass per unit volume
density = mass/volume
d = 100/20
d = 5 g/cm3
So, density of sample is 5 g/cm3
Learn more about Density here:
brainly.com/question/1354972
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Answer:
1.04 s
Explanation:
The computation is shown below:
As we know that
t = t' × 1 ÷ (√(1 - (v/c)^2)
here
v = 0.5c
t = 1.20 -s
So,
1.20 = t' × 1 ÷ (√(1 - (0.5/c)^2)
1.20 = t' × 1 ÷ (√(1 - (0.5)^2)
1.20 = t' ÷ √0.75
1.20 = t' ÷ 0.866
t' = 0.866 × 1.20
= 1.04 s
The above formula should be applied
Answer:
I(x) = 1444×k ×
I(y) = 1444×k ×
I(o) = 3888×k ×
Explanation:
Given data
function = x^2 + y^2 ≤ 36
function = x^2 + y^2 ≤ 6^2
to find out
the moments of inertia Ix, Iy, Io
solution
first we consider the polar coordinate (a,θ)
and polar is directly proportional to a²
so p = k × a²
so that
x = a cosθ
y = a sinθ
dA = adθda
so
I(x) = ∫y²pdA
take limit 0 to 6 for a and o to 
for θ
I(x) = 
y²p dA
I(x) = (a sinθ)²(k × a²) adθda
I(x) = k 
da × 
(sin²θ)dθ
I(x) = k da × (1-cos2θ)/2 dθ
I(x) = k 
× 
I(x) = k × 
× ( 
I(x) = k × 
× 
I(x) = 1444×k × .....................1
and we can say I(x) = I(y) by the symmetry rule
and here I(o) will be I(x) + I(y) i.e
I(o) = 2 × 1444×k ×
I(o) = 3888×k × ......................2
