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djyliett [7]
3 years ago
15

A closed system of mass 10 kg undergoes a process during which there is energy transfer by work from the system of 0.147 kJ per

kg, an elevation decrease of 50 m, and an increase in velocity from 15 m/s to 30 m/s. The specific internal energy decreases by 5 kJ/kg and the acceleration of gravity is constant at 9.7 m/s2. Determine the heat transfer for the process, in kJ.
Physics
1 answer:
anyanavicka [17]3 years ago
5 0

Answer:-50.005 kJ

Explanation:

Given

mass of system =10 kg

work done=0.147 kJ/kg

Change in elevation(\Delta h)=-50 m

initial velocity (v_1)=15 m/s

Final Velocity(v_2)=30 m/s

Specific internal Energy(\Delta U)=-5 kJ/kg

from first Law of thermodynamics

Q-W=\Delta H

\Delta H=\Delta KE+ \Delta PE +\Delta U

where KE= kinetic energy

PE=potential energy

U=internal Energy

\Delta H=\frac{m(v_2^2-v_1^2)}{2}+mg(\Delta h)+\Delta U

Q=W+\Delta KE+ \Delta PE +\Delta U

Q=0.147\times 10+\frac{10\cdot (30^2-15^2)}{2}+10\cdot 9.81\cdot (-5)-5\times 10

Q=1.47+3.375-4.850-50

Q=-50.005 kJ

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