KClO3 ---> KCl + O2 Balance the decomposition chemical reaction. A) KClO3 ---> KCl + O2 B) 2KClO3 ---> KCl + 3O2 C) 2KC
1 answer:
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The heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ.
The heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.
Explanation:
The heat energy required to raise the temperature of any body can be obtained from the specific heat formula. As this formula states that the heat energy required to raise the temperature of the body is directly proportional to the product of mass of the body, specific heat capacity of the material and temperature change experienced by the material.
So in this problem, the mass of the aluminium is given as m = 1500 g, the specific heat of the aluminium is 0.900 J/g °C. Then as it is stated that the temperature is raised by 100 °C, so the pots are heat to increase by 100 °C from its initial temperature. This means the difference in temperature will be 100°C (ΔT = 100°C).
Then, the heat energy required to raise the temperature will be
Thus, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100 °C is 135 kJ.
Similarly, the mass of copper pot is given as 1500 g, the specific heat capacity of copper is 0.385 and the difference in temperature is 100 °C.
Then, the heat energy required to raise its temperature will be
And the heat energy required to raise the temperature of 1500 g of copper pot by 100°C is 57.75 kJ.
So, the heat energy required to raise the temperature of 1500 g of aluminium pot by 100°C is 135 kJ. And the heat energy required to raise the temperature of 1500 g of copper pot by 100 °C is 57.75 kJ.
Answer:
1335.12 mL of H2O
Explanation:
To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).
From the molarity formula we can first calculate the volume of the solution:
The volume of the solution as we said previously is:
Solution volume = solute volume + solvent volume
To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:
Now with the density of NaOH the milliliters of solute can be determined:
Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:
Solvent volume = solution volume - solute volume
Solvent volume = 1429 mL - 93.88 mL = 1335.12 mL of H2O