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nata0808 [166]
3 years ago
5

Dean took out a 10-year loan for $40,000 at an APR of 4% compounded monthly. What will his balance be after he has made exactly

half of his monthly payments
Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer: 21,990.07

Step-by-step explanation: A P E X

damaskus [11]3 years ago
3 0

Answer:

The balance be after he has made exactly half of his monthly payments is $56881.4.

Step-by-step explanation:

Given : Dean took out a 10-year loan for $40,000 at an APR of 4% compounded monthly.

To find : What will his balance be after he has made exactly half of his monthly payments?

Solution :

Formula of monthly payment ,

M=\frac{\text{Amount}}{\text{Discount factor}}  

Discount factor D=\frac{1-(1+i)^{-n}}{i}  

Where, Amount = $40,000

Rate r= 4% compounded monthly

i=\frac{4}{100}=0.04  

Time = 10 years  

n=10\times12=120  

Now, put all the values we get,  

D=\frac{1-(1+i)^{-n}}{i}  

D=\frac{1-(1+0.04)^{-120}}{0.04}  

D=\frac{1-(1.04)^{-120}}{0.04}  

D=\frac{1-0.00903}{0.04}  

D=\frac{0.9909}{0.04}  

D=24.7725  

M=\frac{\text{Amount}}{\text{Discount factor}}  

M=\frac{40000}{24.7725}  

M=1614.69  

Half of the monthly payment is $807.345

Payment for 10 years is 807.345\times 120=96881.4

The balance is $96881.4-$40000=$56881.4

Therefore, The balance be after he has made exactly half of his monthly payments is $56881.4.

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Four times Joe’s age plus 2 times Tim’s ageequals 50. Tim’s age is also 2 less than Joe’s age.How old is Joe?
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Answer:

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Step-by-step explanation:

We can start by creating two different equations, one for each fact that we know about their ages.

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URGENT please help!!! I need a explanation please!! You own a restaurant and can reopen as long as people seated at a table are
hram777 [196]

Answer:

1) Maximum number of tables that can be kept in the dinning room is 10 tables

2)The maximum number of customers, given 6 people per table is 60 customers

Step-by-step explanation:

The parameters given are;

Distance between people seated at different tables = 6 ft

Dimension of table = 2 m by 1.5 m

Number of people at a table = 6 people

Dimension of dinning;

Width = 12 m

Length = 20 m

Dimension of entrance;

Width = 20/21*30  m

Length = 10 m

With 6 meters between tables and a table with of 1.5, we have for the arrangement in the question;

3 tables = 4.5 m

Distance between = 2 × 6 = 12

4.5 + 12 = 16 m (More room required)

With two tables, we have;

Width of tables = 2×1.5 = 3 m

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Dining room width required = 3 + 6 = 9 m

Therefore, the maximum tables in each row = 2

Given that the dining room area extends to the entrance area, total length = 30 m.

With 4 tables we have;

Length = 4 × 2 + 6 × 3 = 26

While on the entrance side of the dinning room area which is 20 m, we have 3 tables;

Length = 3 × 2 + 6 × 2 = 18

Therefore, both arrangements are acceptable;

Just on entering by the right the length = 20/21×30 m

Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning

1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables

2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.

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