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nata0808 [166]
3 years ago
5

Dean took out a 10-year loan for $40,000 at an APR of 4% compounded monthly. What will his balance be after he has made exactly

half of his monthly payments
Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer: 21,990.07

Step-by-step explanation: A P E X

damaskus [11]3 years ago
3 0

Answer:

The balance be after he has made exactly half of his monthly payments is $56881.4.

Step-by-step explanation:

Given : Dean took out a 10-year loan for $40,000 at an APR of 4% compounded monthly.

To find : What will his balance be after he has made exactly half of his monthly payments?

Solution :

Formula of monthly payment ,

M=\frac{\text{Amount}}{\text{Discount factor}}  

Discount factor D=\frac{1-(1+i)^{-n}}{i}  

Where, Amount = $40,000

Rate r= 4% compounded monthly

i=\frac{4}{100}=0.04  

Time = 10 years  

n=10\times12=120  

Now, put all the values we get,  

D=\frac{1-(1+i)^{-n}}{i}  

D=\frac{1-(1+0.04)^{-120}}{0.04}  

D=\frac{1-(1.04)^{-120}}{0.04}  

D=\frac{1-0.00903}{0.04}  

D=\frac{0.9909}{0.04}  

D=24.7725  

M=\frac{\text{Amount}}{\text{Discount factor}}  

M=\frac{40000}{24.7725}  

M=1614.69  

Half of the monthly payment is $807.345

Payment for 10 years is 807.345\times 120=96881.4

The balance is $96881.4-$40000=$56881.4

Therefore, The balance be after he has made exactly half of his monthly payments is $56881.4.

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Ugo [173]

1. Occasionally a savings account may actually pay interest compounded continuously. For each​ deposit, find the interest earned if interest is compounded​ (a) semiannually,​ (b) quarterly,​ (c) monthly,​ (d) daily, and​ (e) continuously. Use 1 year = 365 days.

Principal ​$1031

Rate 1.4%

Time 3 years

Answer:

a) $ 44.07

b) $ 44.15

c) $ 44.20

d) $ 44.22

e) $ 44.22

Step-by-step explanation:

The formula to find the total amount earned using compound interest is given as:

A = P(1 + r/n)^nt

Where A = Total amount earned after time t

P = Principal = $1031

r = Interest rate = 1.4%

n = compounding frequency

t = Time in years = 3 years

For each​ deposit, find the interest earned if interest is compounded

(a) semiannually

This means the interest is compounded 2 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/2) ^2 × 3

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I (interest) = $ 44.07

​(b) quarterly

This means the interest is compounded 4 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/4) ^4 × 3

A = 1031 (1 + 0.014/4)^12

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I = A - P

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P (principal) = $ 1,031.00

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​ This means the interest is compounded 12 times in a year

Hence:

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P (principal) = $ 1,031.00

I (interest) = $ 44.20

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This means the interest is compounded 365 times in a year

Hence:

A = P(1 + r/n)^nt

A = 1031(1 + 0.014/365) ^2 × 3

A = 1031 (1 + 0.00365)^365 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

(e) continuously. .

This means the interest is compounded 2 times in a year

Hence:

A = Pe^rt

A = 1031 × e ^0.014 × 3

A = $ 1,075.22

A = P + I where

I = A - P

I = $1075.22 - $1031

P (principal) = $ 1,031.00

I (interest) = $ 44.22

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