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fgiga [73]
3 years ago
12

Describe what happens to the gravitational force when the Sun, Earth and Moon are in a line.

Physics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

a spring tide occurs

Explanation:

ithe gravitational pull makes that tide happen

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During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc
Lina20 [59]
V o = 6 m/s,
t = 2 s
v = 10 m/s
v = v o + a t
a t = v - v o
a = ( v - v o ) / t 
a = ( 10 m/s - 6 m/s ) / 2 s = 4 m/s / 2 s = 2 m/s²
Answer:
The runner`s acceleration is 2 m/s².
6 0
3 years ago
) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th
Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

    m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w

Now, we will substitute 0 for both z_{1} and z_{2}, 0 for w, 334.9 kJ/kg for h_{1}, 2726.5 kJ/kg for h_{2}, 5 m/s for V_{1} and 220 m/s for V_{2}.

Putting the given values into the above formula as follows.

     m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w  

     1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0

                q = 6597.711 kJ

Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.

6 0
3 years ago
If the speed of an object were to triple, what would be the increase of kinetic energy? KE2 = _____ KE1
Olin [163]
Kinetic energy is directly proportional to the square of their velocities... so if velocity has been increased 3 times, increase in K.E would be: 3^2 = 9

In short, Your Answer would be: KE2 = 9 * KE1

Hope this helps!
5 0
3 years ago
1
Darina [25.2K]

Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1  = 60kg

Mass 2  = 75kg

Distance between the bodies  = 2m

Unknown:

Gravitational fore  = ?

Solution:

The gravitational force between the two bodies can be derived using;

  F  = \frac{G mass 1 x mass 2}{distance^{2} }  

    G is the universal gravitation constant  = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

  F  = \frac{6.67 x 10^{-11}  x 60 x 75}{2^{2} }   = 7.5 x 10⁻⁸N

3 0
3 years ago
A person is pushing a book lying on a table. Identify the different forces that act on
BaLLatris [955]

Explanation:

There are two forces acting upon the book. One force - the Earth's gravitational pull - exerts a downward force. The other force - the push of the table on the book (sometimes referred to as a normal force) - pushes upward on the book.

3 0
3 years ago
Read 2 more answers
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