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HACTEHA [7]
3 years ago
15

A student claims that titanium is the strongest material to fracture. Based on this interaction, which evidence would best suppo

rt the student's claim?
a. Titanium takes the longest time to reach fracture.
b. Titanium has the highest fracture stress value.
c. Titanium deforms the least before fracture.
d. Titanium increases its fracture strength as the load increases.
Engineering
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

b. Titanium has the highest fracture stress value.

Explanation:

Titanium is the strongest material to fracture, according to the student. To support his claim, the evidence should be .. the titanium has the highest stress value for fracture.  

If the materials is having high value of fracture stress it means that it is strong material and it is not easy to break that type of materials.

Therefore the answer will be B.

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Answer:

Length = 129.55m, 129.55m

Explanation:

Given:

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Temperature of water out = 80°C

mass rate of water =1.8 kg/s.

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Temperature at saturation = 120°C

hfg of steam at 120°C = 2203 kJ/kg

overall heat transfer coefficient of the heat exchanger = 700 W/m2 ·°C

U = 700 W/m2 ·°C

Since Temperature of steam is at saturation,

temperature of steam going in = temperature of steam out = 120°C

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Find attached the full solution to the question.

3 0
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Oxygen combines with nitrogen in the air to form NOx at about
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B) Oxygen combines with nitrogen in the air to form NOx at about 2500 degrees Fahrenheit.
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Which is a better hydraulic cross section for an open channel: one with a small or a large hydraulic radius?
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For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Strike441 [17]

Answer:

the elongation of the metal alloy is 21.998 mm

Explanation:

Given the data in the question;

K = σT/ (εT)ⁿ

given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,

strain-hardening exponent n = 0.22

we substitute

K = 345 / 0.02^{0.22

K = 815.8165 Mpa

next, we determine the true strain

(εT) = (σT/ K)^1/n

given that σT = 412 MPa

we substitute

(εT) = (412 / 815.8165 )^(1/0.22)

(εT) = 0.04481 mm

Now, we calculate the instantaneous length

l_i = l_0e^{ET

given that l_0 = 480 mm

we substitute

l_i =480mm × e^{0.04481

l_i =  501.998 mm

Now we find the elongation;

Elongation = l_i - l_0

we substitute

Elongation = 501.998 mm - 480 mm

Elongation = 21.998 mm

Therefore, the elongation of the metal alloy is 21.998 mm

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