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Vilka [71]
3 years ago
9

"My partner seems to be more in the mood at night time, but I'm more in the mood in the morning. Why might that be and is there

anything we can do to get on the same page?"
This is specifly for class only in in science and part class im doing a class and my teachers need us to answer dont not mark flag pleasee
Physics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

I don't get it?

like yhu want us to rate it or?

Explanation:

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What from the following list of statements about vectors is definitely true? (section 3.3) The magnitude of a vector can be smal
Mashcka [7]

Answer:

"Magnitude of a vector can be zero only if all components of a vector are zero."

Explanation:

"The magnitude of a vector can be smaller than length of one of its components."

Wrong, the magnitude of a vector is at least equal to the length of a component. This is because of the Pythagoras theorem. It can never be smaller.

"Magnitude of a vector is positive if it is directed in +x and negative if is is directed in -X direction."

False. Magnitude of a vector is always positive.

"Magnitude of a vector can be zero if only one of components is zero."

Wrong. For the magnitude of a vector to be zero, all components must be zero.

"If vector A has bigger component along x direction than vector B, it immediately means, the vector A has bigger magnitude than vector B."

Wrong. The magnitude of a vector depends on all components, not only the X component.

"Magnitude of a vector can be zero only if all components of a vector are zero."

True.

6 0
3 years ago
A negative charge, q1, of 6 µC is 0. 002 m north of a positive charge, q2, of 3 µC. What is the magnitude and direction of the e
prohojiy [21]

Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

<h3>What is electrical force?</h3>

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is

q₁ is the negative charge = 6 µC=6×10⁻⁶ C

q₂ is the positive charge = 3 µC=3×10⁻⁶ C

r is the distance between the charges=0.002 m

F_E is the electric force =?

The value of electric force will be;

\rm F_E= \frac{Kq_1q_2}{r^2} \\\\ F_E= \frac{9\times 10^9\times 6\times 10^{-6}\times3\times10^{-6}}{(0.002)^2}\\\\ \rm F_E=4.05\times10^4\;N

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.

To learn more about the electrical force refer to the link;

brainly.com/question/1076352

7 0
2 years ago
Suppose a sound wave and a light wave have the same frequency.
dedylja [7]

Answer:

The light wave has a longer wavelength and has the greater speed.

Explanation:

light has a far more greater speed than sound. The speed of sound in air is about 343m/s while that of light is around  3 *10^{8}m/s

wavelength (λ) =\frac{V}{f}

since the frequencies of sound and light are same from the question, the wavelength would depend on the magnitude of their velocities. Light with a higher speed would have a longer wavelength.

5 0
3 years ago
Read 2 more answers
Atmospheric pressure on the peak of Mt. Everest can be as low as 0.197 atm, which is why
lbvjy [14]

Answer:2,030

Explanation:

40 atm x 10.0 L = 400

400/0.197 atm = 2,030

7 0
3 years ago
HELP PLZ
Anon25 [30]

Answer:

A = 11.77 m/s²

Explanation:

Mass of box (m) = 66kg

Force (f) = 777n

Acceleration (a) = ??

F = ma

777 = 66 · a

A = \frac{777}{66} = 11.77m/s²

5 0
2 years ago
Read 2 more answers
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