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Burka [1]
3 years ago
10

. An atom of nitrogen has an atomic

Chemistry
1 answer:
GrogVix [38]3 years ago
5 0

Here's the Answer !

Atomic number = no. of electrons = no. of protons, therefore :

  • no. of electrons = 7

  • no. of protons = 7

and mass number = no. of protons + no. of neutrons

so,

  • 7 + no. of neutrons = 14

  • no. of neutrons = 7
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pogonyaev
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2 years ago
Many metals react with acids to produce hydrogen gas. A certain reaction produces 32.6 L of hydrogen gas at STP. How many moles
morpeh [17]

Answer: 1.46moles

Explanation:

Applying PV= nRT

P= 1atm, V= 32.6L, R= 0.082, T = 273K

Substitute and simplify

1×32.6/(0.082×273)=n

n= 1.46moles

4 0
3 years ago
Why can the same earthquake have different ratings on the 2 scales.
horsena [70]
The scales are different
5 0
3 years ago
Balance the following redox reaction in acidic solution. Zn(s)+MnO−4(aq)→ Zn+2(aq)+Mn+2(aq)
devlian [24]

Answer:

2MnO₄⁻ + 5Zn + 16H⁺ → 2Mn²⁺ + 8H₂O + 5Zn²⁺

Explanation:

To balance a redox reaction in an acidic medium, we simply follow some rules:

  1. Split the reaction into an oxidation and reduction half.
  2. By inspecting, balance the half equations with respect to the charges and atoms.
  3. In acidic medium, one atom of H₂O is used to balance up each oxygen atom and one H⁺ balances up each hydrogen atom on the deficient side of the equation.
  4. Use electrons to balance the charges. Add the appropriate numbers of electrons the side with more charge and obtain a uniform charge on both sides.
  5. Multiply both equations with appropriate factors to balance the electrons in the two half equations.
  6. Add up the balanced half equations and cancel out any specie that occur on both sides.
  7. Check to see if the charge and atoms are balanced.

Solution

                            Zn + MnO₄⁻ → Zn²⁺ + Mn²⁺

The half equations:

                      Zn → Zn²⁺                          Oxidation half

                      MnO₄⁻ → Mn²⁺                  Reduction half

Balancing of atoms(in acidic medium)

                     Zn → Zn²⁺

                    MnO₄⁻ + 8H⁺ → Mn²⁺ + 4H₂O

Balancing of charge

                   Zn → Zn²⁺ + 2e⁻

                    MnO₄⁻ + 8H⁺ + 5e⁻→ Mn²⁺ + 4H₂O

Balancing of electrons

         Multiply the oxidation half by 5 and reduction half by 2:

                          5Zn → 5Zn²⁺ + 10e⁻

                        2MnO₄⁻ + 16H⁺ + 10e⁻→ 2Mn²⁺ + 8H₂O

Adding up the two equations gives:

              5Zn + 2MnO₄⁻ + 16H⁺ + 10e⁻ → 5Zn²⁺ + 10e⁻ + 2Mn²⁺ + 8H₂O

The net equation gives:

         5Zn + 2MnO₄⁻ + 16H⁺ → 5Zn²⁺ + 2Mn²⁺ + 8H₂O

8 0
3 years ago
Two substances that have the same number of moles of representative particles always have: Answer the same number of atoms the s
Nesterboy [21]
<span>same no of atoms
b/c no. of atoms = moles * avogadro's no (6.022 X 10^23)</span>
7 0
3 years ago
Read 2 more answers
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