<u>Answer:</u> The initial molarity of cation is 2.38 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of 
= 46.3 g
Molar mass of = 129.6 g/mol
Volume of solution = 150 mL
Putting values in above equation, we get:
1 mole of produces 1 mole of 
cation and 1 mole of 
anion
So, molarity of cation = (1 × 2.38) = 2.38 M
Hence, the initial molarity of cation is 2.38 M
Lets assume that 100 grams of the compound are present.
Carbon mass: 88.14 g
Hydrogen mass: 11.86 g
Moles carbon: 88.14/12 = 7.34
Moles hydrogen: 11.86/1 = 11.86
The moles of carbon are 7.34 and the moles of hydrogen are 11.86.
Answer:
The answer is 17.03052. We assume you are converting between grams Ammonia and mole.
