Answer:
−153.1 J / (K mol)
Explanation:
Calculate the standard entropy of reaction at 298 K for the reaction Hg(liq) + Cl2(g) → HgCl2(s) The standard molar entropies of the species at that temperature are: Sºm (Hg,liq) = 76.02 J / (K mol) ; Sºm (Cl2,g) = 223.07 J / (K mol) ; Sºm (HgCl2,s) = 146.0 J / (K mol)
Hg(liq) + Cl2(g) → HgCl2(s)
Given that;
The standard molar entropies of the species at that temperature are:
Sºm (Hg,liq) = 76.02 J / (K mol) ;
Sºm (Cl2,g) = 223.07 J / (K mol) ;
Sºm (HgCl2,s) = 146.0 J / (K mol)
The standard molar entropies of reaction = Sºm[products] - Sºm [ reactants]
= 146.0 J / (K mol) – [76.02 J / (K mol) +223.07 J / (K mol) ]
= -153.09 J / (K mol)
= or -153.1 J / (K mol)
Hence the answer is −153.1 J / (K mol)
Vapor pressure of a liquid increases with increasing temperature because increasing the temperature results in increasing kinetic energy and increase in molecular transition and motion.
What is Vapor Pressure?
- The pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases (solid or liquid) at a specific temperature in a closed system is referred to as vapor pressure.
- A liquid's evaporation rate can be determined by looking at the equilibrium vapor pressure. It has to do with how often particles tend to float away from liquids (or a solid).
- Volatile is a term used to describe a chemical that has a high vapor pressure at room temperature. Vapor pressure is the force that vapor exerts when it is present above a liquid surface.
- A liquid's molecules have an increasing kinetic energy as its temperature rises. The more molecules that convert into a vapor as a result of an increase in molecular kinetic energy, the higher the vapor pressure will be.
Know more about vapor pressure brainly.com/question/14617982
#SPJ4
Answer:
lymphocytes
Explanation:
it consists of the b and the t cells
Answer:
See explanation
Explanation:
We know that the thermal energy of a substance largely depends on the temperature of the body. This implies that the hotter a substance is, the greater its thermal energy and vice versa.
When you bring a cold can of soda out of the refrigerator, the molecules of air at room temperature gradually loose energy to the can and condense around it. This transfers thermal energy from the air particles to the molecules in the cold can of soda and the soda warms up pretty soon!