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mote1985 [20]
3 years ago
14

A sample of nitrogen monoxide occupies a volume of 400 mL at 100 °C and 720 mmHg.

Chemistry
1 answer:
konstantin123 [22]3 years ago
6 0
The volume of nitrogen  monoxide that   occupy  at  STP  is=  277  Ml

     calculation
 The volume is obtained  using   the combined  gas law  that is P1V1/T1= P2V2?
Where  P1 = 720  MmHg
            V1 = 400ml
           T1= 100 +273=  373 K
At  STP  temperature  =  273 K  and  pressure=  760 mm  hg
therefore T2=  273 k
               p2 = 760  mmhg
               V2=?
make  V2  the subject of the formula

V2= (T2 ×P1 ×V1)/(P2×T1)

V2  is therefore  = (273k  x720 mmhg x 400 ml)/(760 mmhg x373K) = 277  Ml
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Which of the following would have the slowest rate of diffusion at a given temperature
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ILL MARK BRAINLIEST :)
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Explanation:

According to the law of conservation of mass, mass can neither be created nor destroyed but it can simply be transformed from one form to another.

For example, Na^{+} + Cl^{-} \rightarrow NaCl

Mass of Na = 23 g/mol

Mass of Cl = 35.5 g/mol

Sum of mass of reactants = mass of Na + mass of Cl

= 23 + 35.5 g/mol

= 58.5 g/mol

Mass of product formed is as follows.

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= (23 g/mol + 35.5) g/mol

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3 0
3 years ago
The two naturally occuring isotopes of antimony are 121Sb (57.21%) and 123Sb (42.79%), with isotopic masses of 120.904 and 122.9
emmasim [6.3K]

Answer:

The average atomic weight = 121.7598 amu

Explanation:

The average atomic weight of natural occurring antimony can be calculated as follows :

To calculate the average atomic mass the percentage abundance must be converted to decimal.

121 Sb has a percentage abundance of 57.21%, the decimal format will be

57.21/100 = 0.5721 . The value is the fractional abundance of 121 Sb .

123 Sb has a percentage abundance of 42.79%, the decimal format will be

42.79/100 = 0.4279. The value is the fractional abundance of 123 Sb .

Next step is multiplying the fractional abundance to it masses

121 Sb = 0.5721 × 120.904 = 69.169178400

123 Sb = 0.4279 × 122.904 = 52.590621600

The final step is adding the value to get the average atomic weight.

69.169178400 + 52.590621600 = 121.7598 amu

5 0
3 years ago
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