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Rufina [12.5K]
3 years ago
11

Which is the most active nonmetallic element in group 16?

Chemistry
1 answer:
timama [110]3 years ago
5 0
Oxygen

For metals, reactivity increases as we move through the elements in the period table from top to bottom, and left to right. In contrast, for nonmetals, reactivity increases as we move through the elements in the periodic table, as we move from bottom to the top, and right to left. 

Group 16 on the periodic table is also called the oxygen family or chalcogens. It includes the following elements from top to bottom: Oxygen, Sulfur, Selenium, Tellurium, and Polonium. Of these, only Oxygen, Sulfur, and Selenium are nonmetals. Since reactivity of nonmetals increases going up the periodic table, oxygen is therefore the most reactive nonmetal in the group. Shown in the figure below is the reactivity trend in the periodic table.

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In matter results in a change in its identity and properties.
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Answer:

The chemical change in matter is results in a change in its identity and properties.

Explanation:

There are toe type of changes physical change and chemical change.

The chemical change change in matter lead to lost its identity and properties.

Chemical change:

The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.

These changes are irreversible

These changes occur due to chemical reactions

These may not be observed with naked eye

Example:

Combustion of fuel or wood: that oil or wood convert into energy, CO2 and ash in case of wood

Boiling of egg: that change the chemical composition of protein in the egg .

The reaction of Hydrogen and oxygen:  

H 2 (g)  + O 2  (g) -------------------------------------> 2H 2O  (l)

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What process occurs during the corrosion of iron?
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Answer:

A

Explanation:

The iron corrodes so it oxidized

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Read 2 more answers
You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions
artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0
3 years ago
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