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svetlana [45]
4 years ago
12

Two students designed an experiment to study the effect of solar radiations on four cities of Earth. They used a globe to repres

ent Earth and a light bulb to represent the sun. The four cities were labeled A, B, C, and D on the globe at the latitudes shown in the chart below. City Latitude A 33° 53' S B 64° 03' N C 39° 56' N D 2° 09' S The students moved the globe slowly around the light bulb in an elliptical orbit. Based on the experiment, the students are most likely to conclude that the least variation in seasons will be experienced at City A City B City C City D
Physics
1 answer:
Furkat [3]4 years ago
3 0
Great experiment !  Everybody should try it if they can get the equipment. 
It demonstrates a lot of things that are very hard to explain in words. 

I hope the students remembered to tilt the axis of the globe.  If they didn't,
and instead kept it straight up and down, then each city had pretty much
the same amount of bulb-light all the way around, and there were no seasons.

If the axis of the globe was tilted, then City-D had the least variation in
seasons.  City-D is only 2° from the equator, so the sun is more direct
there all year around than it is at any of the others.
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Potential difference is the work done in moving a positive test charge from infinity to the point in question.

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By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
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Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

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\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

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We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

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4 years ago
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