Electricity can travel in a(n) _______ circuit.<br> closed<br> open<br> short<br> electromagnetic

imagine riding a single-speed bicycle. why do you have to push harders on the pedals to start the bicycle moving than to keep it

Flura [38]

A large force is required to accelerate the mass of the bicycle and rider. Once the desired constant velocity is reached, a much smaller force is sufficient to overcome the ever-present frictional forces.

3 0

2 years ago

The electric current leaves the battery through the --- complete this blank

aev [14]

The bulb

Hope this helps!

5 0

3 years ago

What types of cells are likely to have lots of smooth ER?

Andrei [34K]

Answer:

eukaryotic cells

Explanation:

"Smooth endoplasmic reticulum (sER) is (a part of) endoplasmic reticulum that is tubular in form and lacks ribosomes. It is present in eukaryotic cells and is associated with lipid synthesis, carbohydrate metabolism, regulation of calcium concentration, and drug detoxification"

source: biologyonline

8 0

2 years ago

How many ohms of resistance must be present in a circuit that has 240 volts and a current of 15 amps?

PIT_PIT [208]

Answer:

16 ohms

Explanation:

V= I ⋅ R

where, V is the net potential difference in the circuit, I is the current in the circuit and R is the net resistance of the circuit.

In this case, V = 240 volts, I = 15 amperes.

240 = 15 ⋅ R

⇒ R = 240/ 15 = 16 ohms

5 0

3 years ago

Read 2 more answers

A child of mass 40.0 kg is in a roller coaster car that travels in a loop of radius 7.00 m. at point a the speed of the car is 1

pav-90 [236]

I attached the missing picture.
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
There two forces acting on the child. The first one is the gravitational force and the second one is centrifugal force. In this example, the force of gravity is always pulling down, but centrifugal force always acts away from the center of circular motion.
Part A
For point A we have:
$F_a=F_cf-F_g$
In this case, the forces are aligned, centrifugal is pointing up and gravitational is pulling down.
$F_a=m\frac{v^2}{r}-mg=179 $N$
Part B
At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
$F=F_{cf}\cos(30)-mg=m\frac{v^2}{r}\cos(30)-mg=153.2$N$
Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance:
$F_g=F_{cf}\\
mg=m\frac{v^2}{r}\\
gr=v^2\\
v=\sqrt{gr}=8.29\frac{m}{s}$

6 0

2 years ago

Electricity can travel in a(n) _______ circuit. closed open short electromagnetic