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Colt1911 [192]
3 years ago
7

Convert the following quantities

0%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="25m {}^{2} \: into \: cm {}^{2} " alt="25m {}^{2} \: into \: cm {}^{2} " align="absmiddle" class="latex-formula">
​
Physics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

\rm 250000 \; cm^2

Explanation:

Refer to the attachment.

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Difference betwwen Acclerat<br>ion and retradation​
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I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration
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3 years ago
1. A ball is thrown vertically upward.
Ghella [55]

Answer:

The acceleration increases.

Explanation:

hope this helps

4 0
3 years ago
The bricks are homogeneous and have the same mass. Each brick is 5.00 cm
Kitty [74]

Answer:

(5/3,-5/6) or (1.67, -0.83)

Explanation:

the center if there are 4 bricks is the point 0,0 or intersection of the two arrow.

if we remove one on the top left, with the center of the mass in (-5,2.5), the the new coordinates of the center of mass can be found like this

x = A1 x1 - A2 x2 / (A1 - A2)

x = new coordinate of the system

A1 is the Area of 4 bricks = 20 x 10 = 200 cm²

A2 is the Area of 1 brick we remove, the top left = 10 x 5 = 50 cm²

x1 = the x coordinate of the center of mass when there are 4 bricks, x = 0

x2 = the x coordinate of the center of mass of the remove brick, x = -5

x = (200 . 0) - (50 . (-5))/(200 - 50)

x = - (-250) / 150

x = 250/150 = 5/3 = 1.67 cm

we can find the value y of the new coordinate, the same way we find x

y = A1 y1 - A2 y2 / (A1 - A2)

y = (200 . 0) - (50 . 2.5) / (200-50)

y = - 125/150

y = -5/6 = -0.83 cm

4 0
3 years ago
An apparatus like the one Cavendish used to find G has large lead balls that are 8.4 kg in mass and small ones that are 0.061 kg
garik1379 [7]

Answer:

The gravitational force is 1.05\times10^{-8}\ N

Explanation:

Given that,

Mass of large ball = 8.4 kg

Mass of small ball = 0.061 kg

Separation = 0.057 m

Gravitational constant G= 6.67\times10^{-11}\ Nm^2/kg^2

We need to calculate the gravitational force

Using formula of gravitational force

F= \dfrac{Gm_{1}m_{2}}{r^2}

Put the value into the formula

F=\dfrac{6.67259\times10^{-11}\times8.4\times0.061}{(0.057)^2}

F=1.05\times10^{-8}\ N

Hence,  The gravitational force is 1.05\times10^{-8}\ N

6 0
3 years ago
The track of a roller coaster is shown below. At which point will the riders experience centripetal acceleration?
valentinak56 [21]

Centripetal acceleration is applied in circular motion. Y is the point on the track that most closely resembles a circular path for the roller coaster.

4 0
3 years ago
Read 2 more answers
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