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Colt1911 [192]
2 years ago
7

Convert the following quantities

0%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="25m {}^{2} \: into \: cm {}^{2} " alt="25m {}^{2} \: into \: cm {}^{2} " align="absmiddle" class="latex-formula">
​
Physics
1 answer:
Bad White [126]2 years ago
8 0

Answer:

\rm 250000 \; cm^2

Explanation:

Refer to the attachment.

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The thermal expansion of a solid is caused by:
Shkiper50 [21]

Answer:

C

Explanation:

The increase in the distance between equilibrium positions for the vibrating atoms.

6 0
3 years ago
Consider an oblique shock wave with a wave angle of 35 o . Upstream of the wave, the static pressure and temperature are 2,000 l
ziro4ka [17]

Answer:

The pressure is 6570  lbf/ft²

The temperature is 766 ⁰R

The velocity is 2746.7 ft/s

deflection angle behind the wave is 17.56⁰

Explanation:

Speed of air at initial condition:

a_1 = \sqrt{\gamma RT } =  \sqrt{1.4* 1716*520 } = 1117.70 \ ft/s

γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.

initial mach number

M_1 = \frac{v_1}{a_1} = \frac{3355}{1117.7}  = 3

then, M_n = M_1sin \beta = 3sin(35) = 1.721

based on the values obtained, read off the following from table;

P₂/P₁ = 3.285

T₂/T₁ = 1.473

Mₙ₂ = 0.6355

Thus;

P₂ = 3.285P₁ = 3.285(2000) = 6570  lbf/ft²

T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R

Again; to determine the velocity and deflection angle, first we calculate the mach number.

M_t_1 = M_1cos \beta = 3 cos(35) = 2.458

w_2 = a_1M_t_1 = 2.458(1117.70) = 2746.7 \ ft/s

a_2 = \sqrt{\gamma RT_2} = \sqrt{1.4*1718*766} = 1357.34 \ ft/s

v_2 = a_2M_n_2 = 1357.34(0.6355) = 862.59 \ ft/s

Tan(\beta -\theta) = \frac{v_2}{w_2} = \frac{862.59}{2746.7}  \\\\Tan(\beta -\theta) = 0.314\\\\\beta -\theta= 17.44\\\\\theta = \beta - 17.44 = 17.56^o

6 0
3 years ago
4. A free body diagram of a brick on
Otrada [13]

Answer:

bn

nnnnnnnnn

Explanation:

8 0
3 years ago
At TTT = 14 ∘C∘C, how long must an open organ pipe be to have a fundamental frequency of 262 HzHz ? The speed of sound in air is
Stolb23 [73]

Answer:

Length of pipe organ(L) = 0647 m (Approx)

Explanation:

Given:

Temperature (T) = 14°C

Fundamental frequency (F) = 262 Hz

Speed of sound (v) = 331 + 0.60(T) m/s

Find:

Length of pipe organ(L)

Computation:

Speed of sound (v) = 331 + 0.60(14) m/s

Speed of sound (v) = 339.4

Length of pipe organ(L) = Speed of sound (v) / 2(Fundamental frequency)

Length of pipe organ(L) = 339.4 / 2 (262)

Length of pipe organ(L) = 0647 m (Approx)

7 0
3 years ago
Problem 3 A person is standing in a room. Air temperature is 20 C. Assuming that his surface temperature is 30 C, calculate the
PilotLPTM [1.2K]

Answer:

the heat flux between the person and the room = 6.0036 x 10 17 w/m2

Explanation:

The appropriate formular for the steffan boltzmann constant is used as it relates to the heat flux and the steps is as shown in the attachment.

6 0
3 years ago
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