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Colt1911 [192]
2 years ago
7

Convert the following quantities

0%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="25m {}^{2} \: into \: cm {}^{2} " alt="25m {}^{2} \: into \: cm {}^{2} " align="absmiddle" class="latex-formula">
​
Physics
1 answer:
Bad White [126]2 years ago
8 0

Answer:

\rm 250000 \; cm^2

Explanation:

Refer to the attachment.

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Which of the following are true for acceleration?
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A mass weighting 16 lbs stretches a spring 3 inches. The mass is in a medium that exerts a viscous resistance of 20 lbs when the
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Answer:

The equation for the object's displacement is u(t)=0.583cos11.35t

Explanation:

Given:

m = 16 lb

δ = 3 in

The stiffness is:

k=\frac{m}{\delta } =\frac{16}{3} =5.33lb/in

The angular speed is:

w=\sqrt{\frac{k}{m} } =\sqrt{\frac{5.33*386.4}{16} } =11.35rad/s

The damping force is:

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u = 4 ft/s = 48 in/s

Replacing:

c=\frac{F_{D} }{u} =\frac{20}{48} =0.42lbs/in

The critical damping is equal:

c_{c} =\frac{2k}{w} =\frac{2*5.33}{11.35} =0.94lbs/in

Like cc>c the system is undamped

The equilibrium expression is:

u(t)=u(o)coswt+u'(o)sinwt\\u(o)=7=0.583\\u'(o)=0\\u(t)=0.583coswt\\u(t)=0.583cos11.35t

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3 years ago
A wave with a greater amplitude will transfer . . . . \
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Sort the following forces as relevant or not relevant to this situation. The symbols are defined as follows: normal force = n⃗ ,
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10-84

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3 years ago
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