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3 years ago

7

Convert the following quantities

0%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="25m {}^{2} \: into \: cm {}^{2} " alt="25m {}^{2} \: into \: cm {}^{2} " align="absmiddle" class="latex-formula">

1 answer:

Bad White [126]3 years ago

8 0

Answer:

$\rm 250000 \; cm^2$

Explanation:

Refer to the attachment.

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Which can lead to an inaccurate tympanic temperature reading?

lozanna [386]

Significant ear drainage or a scarred tympanic membrane can lead to inaccurate results on a tympanic temperature reading.

<h3>Why inaccurate tympanic temperature reading?</h3>

Significant ear drainage or a scarred tympanic membrane can lead to inaccurate results on a tympanic temperature reading.

Although an ear infection or the presence of an ear infection will not significantly affect a tympanic thermometer reading.

If the client has been sleeping on one side, take the temperature on the other side as heat may be increased on the side against the pillow.

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2 years ago

s it possible for a system to have negative potential energy? Is it possible for a system to have negative potential energy? No,

frez [133]

Answer: Yes it possible for a system to have negative potential energy, since the choice of the zero of potential energy is arbitrary.

Explanation:

Potential energy is defined as the energy present in an object due to its position.

Mathematically, P.E = mgh

A potential energy can be negative also. This is because zero potential energy is arbitrary. For example, at the top of a building the choice of potential energy can be zero.

Therefore, the potential energy below the building will be negative.

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4 years ago

2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind

Alex777 [14]

The resultant speed of the plane is (3) 226 m/s

Why?

We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).

So, calculating we have:

$ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}$

$ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}$

Hence, we have that the resultant speed of the plane is (3) 226 m/s

Have a nice day!

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3 years ago

at top speed an amazon river dolphin can swim 6 miles in 30 minutes what is the river dolphin's speed in miles per hour

hjlf

If it runs 6 miles in half an hour multiply 6 by two then there is your answer

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3 years ago

Read 2 more answers

A ship maneuvers to within 2.50 x 103 m of anisland's 1.80 x 103 m high mountain peak and fires aprojectile at an enemy ship 6.1

const2013 [10]

Answer:

Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m

Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m

Explanation:

Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.

H = (v₀² Sin²θ)/2g

v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s

θ = 75°, g = 9.8 m/s²

H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m

Range of projectile

R = v₀² (sin2θ)/g

R = 250² (sin2×75)/9.8

R = 250² (sin 150)/9.8 = 3188.8 m

Height of mountain = 1.80 × 10³ = 1800 m

Maximum height of projectile = 2975.2 m

Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m

Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m

Range of projectile = 3188.8 m

Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m

8 0

4 years ago