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aivan3 [116]
3 years ago
13

A proton has a charge of 1.6 × 10-19 C and a mass of 1.67 × 10-27 kg. A proton moves with velocity 1.8 × 105 m/s in the z-direct

ion. A magnetic field with B = 2.1 × 10-1 T points in the y-direction. Find the magnitude and direction of the magnetic force on the proton.
What is the angle between the proton’s velocity and the magnetic field?
45°
90°
180°
50°

I'll report you if you don't actually help. I'd like an actual explanation, please.
Physics
1 answer:
lord [1]3 years ago
6 0

Hey

So first we need to know what the direction of the force is, using your right hand rule point your right hand in the direction of the velocity. You're saying its the z direction, not telling me whether it's into the page or out? Since its a positive z im assuming its coming out. The magnetic field is pushing it upwards, so the force is going in the negative x direction.

The force of a magnetic field is

F = Qv X B

What's weird is that you don't need mass in this equation. Actually you don't even need the formula, its telling you that they're all going in perpendicar directions. the answer is 90 degrees.

Now if you want to know the F just multiply the charge, velocity and magnetic field .

F = GVB

F = 6.048 E -15

Answer : 90 degrees, sin(90) = 1

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Water in a tank which is positioned 5 feet above the ground is _____ potential energy? (answers would be like thermal, electric,
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Mechanical

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What is the role of electrical forces in nuclear fission
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Astronomers build optical telescopes on tops of mountains because a. there is less air to dim the light. b. the seeing is better
V125BC [204]

Answer: choices a and b

Explanation:

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6 0
2 years ago
Assume the motions and currents mentioned are along the x axis and fields are in the y direction. (a) does an electric field exe
matrenka [14]
<span> (a) does an electric field exert a force on a stationary charged object? 
Yes. The force exerted by an electric field of intensity E on an object with charge q is
</span>F=qE
<span>As we can see, it doesn't depend on the speed of the object, so this force acts also when the object is stationary.

</span><span>(b) does a magnetic field do so?
No. In fact, the magnetic force exerted by a magnetic field of intensity B on an object with  charge q and speed v is
</span>F=qvB \sin \theta
where \theta is the angle between the direction of v and B.
As we can see, the value of the force F depends on the value of the speed v: if the object is stationary, then v=0, and so the force is zero as well.

<span>(c) does an electric field exert a force on a moving charged object? 
Yes, The intensity of the electric force is still
</span>F=qE
<span>as stated in point (a), and since it does not depend on the speed of the charge, the electric force is still present.

</span><span>(d) does a magnetic field do so?
</span>Yes. As we said in point b, the magnetic force is
F=qvB \sin \theta
And now the object is moving with a certain speed v, so the magnetic force F this time is different from zero.

<span>(e) does an electric field exert a force on a straight current-carrying wire?
Yes. A current in a wire consists of many charges traveling through the wire, and since the electric field always exerts a force on a charge, then the electric field exerts a force on the charges traveling through the wire.

</span><span>(f) does a magnetic field do so? 
Yes. The current in the wire consists of charges that are moving with a certain speed v, and we said that a magnetic field always exerts a force on a moving charge, so the magnetic field is exerting a magnetic force on the charges that are traveling through the wire.

</span><span>(g) does an electric field exert a force on a beam of moving electrons?
Yes. Electrons have an electric charge, and we said that the force exerted by an electric field is
</span>F=qE
<span>So, an electric field always exerts a force on an electric charge, therefore on an electron beam as well.

</span><span>(h) does a magnetic field do so?
Yes, because the electrons in the beam are moving with a certain speed v, so the magnetic force
</span>F=qvB \sin \theta
<span>is different from zero because v is different from zero.</span>
6 0
3 years ago
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