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ra1l [238]
4 years ago
14

1 Which statement BEST describes how a golf club does "work" on a golf ball? (A) When the club hits the ball the club transfers

all of its kinetic energy to the ball. (B) All of the kinetic energy from the club is transferred to the ball as they both move through the air. (C) Some of the kinetic energy from the golf club is transferred to the ball and some transforms into sound and heat, but the total energy remains the same. (D) The golf club loses kinetic energy when it hits the ball and the ball gains kinetic energy from the air as it travels.
Physics
1 answer:
artcher [175]4 years ago
7 0

Answer:

(C) Some of the kinetic energy from the golf club is transferred to the ball and some transforms into sound and heat, but the total energy remains the same.

Explanation:

According to the law of conservation of energy, the total energy of a closed system is constant.

In this problem, the main type of energy involved is the kinetic energy.

Kinetic energy is the energy possessed by an object due to its motion; mathematically, it is calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

In this problem, at the beginning, the golf club is moving, therefore it has kinetic energy.

Then, the club hits the ball, which is put in motion: therefore, the ball has acquired kinetic energy as well. This energy has been transferred from the golf club, which has therefore lost part of its energy.

At the same time, sound and heat are produced in the collision between the golf club and the ball. Since the total energy must be conserved, this means that the initial kinetic energy of the golf club must be equal to the sum of ball's kinetic energy + sound energy + heat energy released in the collision.

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18. Two objects, X and Y. accelerate from rest with the same constant acceleration. Object X accelerates for
zvonat [6]

Answer:

e. Object X has traveled four times as far as object Y.

Explanation:

The distance covered by an object in uniform accelerated motion is given by:

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

The two objects in the problem have same initial velocity, u = 0 (since they start from rest), so we can rewrite the equation as

d=\frac{1}{2}at^2

We see that the distance covered is proportional to the square of the time. In this problem, the two objects X and Y have same acceleration, but object X accelerates for twice the time: since d \propto t^2, this means that the distance covered by X will be 2^2 = 4 times higher that the distance covered by object Y.

4 0
3 years ago
Which type of rock can only form below earths surface?
Inessa [10]

Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous

Explanation:

7 0
2 years ago
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(TCO-8) A band-pass filter has fC1 = 5 kHz and fC2 = 88 kHz. Calculate Bandwidth (BW) and center frequency (fo) for this filter.
Temka [501]

Bandwidth is the difference between the upper and lower frequencies in a continuous band of frequencies.

Mathematically can be expressed as,

BW = F_{c2}-F_{c1}

The upper frequency is 88Hz and the lower frequency is 6, therefore the Bandwidth would be,

BW = (88-5)kHz

BW = 83kHz

The center frequency is given on the basis of the square root of the multiplication of the two reference frequencies, then,

f_0 = \sqrt{f_{c1}*f_{c2}}

f_0 = \sqrt{88*5}

f_0 = 20.97kHz

7 0
3 years ago
I need help with question 8 and 9
Wewaii [24]

8) The height of the shelf is 2.04 m

9) The gravitational potential energy is 100 J

Explanation:

8)

The gravitational potential energy of an object is given by:

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the heigth of the object, relative to the ground

For the object in this problem, we have

m = 10 kg

g=9.8 m/s^2

And we know that

PE = 200 J

Therefore we can re-arrange the formula to solve for h, the heigth of the object:

h=\frac{PE}{mg}=\frac{200}{(10)(9.8)}=2.04 m

9)

As before, the gravitational potential energy of the object is given by:

PE=mgh

where in this  case, we have:

m = 10 kg is the mass of the object

h = 2.04 m is the height of the object from the ground

While in this case, the acceleration of gravity on this planet is

g=4.9 m/s^2

Substituting,

PE=(10)(4.9)(2.04)=100 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

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7 0
4 years ago
Light of wavelength O is passed through a diffraction grating with N lines/meter and then lands on a screen a distance L from th
rodikova [14]

Condition for diffraction

dsin\theta = m\lambda

Where

a = Distance between slits

m = Order of the fringes

\lambda = Wavelength

\theta = At the angle between the ray of light and the projected distance perpendicular between the two objects

For small angles

sin\theta = \approx tan\theta

Where

tan\theta = \frac{Y}{L}

Where L is the distance between the slits and Y the length of the light.

Replacing we have

d\frac{Y}{L} = \lambda m

Y = \frac{m\lambda L}{d}

The distance between slits d can be expressed also as d= \frac{L}{N} Where N is the number of the fringes, then

Y_n = mN\lambda L

Similarly when there is added a new Fringe we have the change of the distance would be :

Y_{n+1} = (m+1)N\lambda L

Linear distance between fringes is

\Delta Y = \Delta Y_{m+1}-Y_m

\Delta Y = (m+1)N\lambda L - mN\lambda L

Therefore the answer is

\Delta Y = N\lambda L

8 0
3 years ago
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