1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fudgin [204]
2 years ago
15

Draw a reaction energy profile (energy vs dihedral angle) for rotation about the c-c bond in ethane. Show the Newman projections

for the minima and maxima in the reaction energy profile.

Chemistry
1 answer:
astraxan [27]2 years ago
8 0

Answer:

The energy profile for rotation about the C-C bond in ethane is shown in the image, along with the Newman projections of the corresponding ethane conformer.

Explanation:

If you see the ethane molecule (second image) from the C-C bond axis (third image), as in the Newman projections, it's easy to draw an angle between one of the hydrogen atoms of the visible carbon, the carbon itself, and one of the hydrogens of the hidden carbon.

When you make a rotation about the C-C bond, the angle between those hydrogens will change. If you start with an eclipsed conformation, with each hydrogen of the hidden C exactly behind the hydrogens of the visible C, the angle will be 0°, or also 120° or 240°, as this rotations will be equivalent. On the other hand, if the angle is 60° (or 180°, or 300°), you will have a staggered conformation. The eclipsed conformation is less stable than the staggered one, because the interactions between hydrogens will be bigger (the repulsion between their electrons), and because of that the eclipsed conformations will be found in the maxima, while the staggered one will be found in the minima.

You might be interested in
What is the formula for Chromium (III) Bisulfite?​
Anit [1.1K]

Answer:

Cr2(SO4)3

Explanation:

6 0
2 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the
choli [55]

Answer:

...................................................

3 0
3 years ago
In part A, when you added water to the sodium acetate in the flask, some of the chemical dissolved into the water. Would you cal
viktelen [127]

Answer: The solution is a SATURATED solution.

Explanation:

Although most substances are soluble in water, some are more soluble than others,that is , their solubilities differ. SOLUBILITY is a means of comparing the extent to which different solutes can dissolve in a particular solvent at a definite temperature.

From the question above, when water was added to the sodium acetate in the flask, SOME of the chemical dissolved into the water, meaning that some remained undissolved. This is because a given volume of water can only dissolve a certain amount of chemical in it at room temperature. If more chemical is added to such a solution, the chemical will remain undissolved. Such a chemical solution is said to be a SATURATED SOLUTION.

A saturated solution of a solute at a particular temperature is on which contains as much solute as it can dissolve at that temperature in the presence of undissolved solute particles.

Unsaturated solution is a type of solution that dissolves all its solutes with no presence of undissolved solute.

Supersaturated solution is one which contains more of the solute than it can normally hold at that temperature. It is an unstable solution which crystallizes out when disturbed.

4 0
3 years ago
Read 2 more answers
Calculate the ph of a 0.60 m h2so3, solution that has the stepwise dissociation constants ka1 = 1.5 × 10-2 and 1.82 1.06 1.02 2.
Vsevolod [243]
Missing in your question Ka2 =6.3x10^-8
From this reaction:
 H2SO3 + H2O ↔ H3O+  + HSO3-
by using the ICE table :
                H2SO3     ↔    H3O     +    HSO3- 
intial         0.6                     0                  0
change     -X                      +X                +X
Equ         (0.6-X)                  X                   X

when Ka1 = [H3O+][HSO3-]/[H2SO3]
So by substitution:
1.5X10^-2 = (X*X) / (0.6-X) by solving this equation for X
∴ X = 0.088
∴[H2SO3] = 0.6 - 0.088 = 0.512
[HSO3-] = [H3O+] = 0.088

by using the ICE table 2:
                 HSO3-     ↔   H3O     +     SO3-
initial        0.088              0.088              0
change    -X                      +X                   +X
Equ         (0.088-X)          (0.088+X)          X

Ka2= [H3O+] [SO3-] / [HSO3-]
we can assume [HSO3-] =  0.088 as the value of Ka2 is very small
 6.3x10^-8 = (0.088+X)*X / 0.088
X^2 +0.088 X - 5.5x10^-9= 0 by solving this equation for X
∴X= 6.3x10^-8
∴[H3O+] = 0.088 + 6.3x10^-8
               = 0.088 m ( because X is so small)
∴PH= -㏒[H3O+]
       = -㏒ 0.088 = 1.06 
5 0
3 years ago
Read 2 more answers
What was the biggest challenge you faced in getting to where you are today and how did you overcome it?
Alchen [17]
It’s all based on you but yours could be anything hard you went through and how you overcame it. Also say how it made you the person you are today
4 0
2 years ago
Other questions:
  • 1. In any nuclear reaction, nuclei are transformed in some way.
    12·2 answers
  • Why can gas be smelled from your kitchen into your bedroom? Thanks!
    15·1 answer
  • Part ii 1. the solubility of _____________ is least affected by temperature. (name of substance)
    5·1 answer
  • What is the molar mass of copper(II)nitrate
    5·2 answers
  • An atom contains 8 protons, 8 neutrons and 10 electrons. A second atom
    7·1 answer
  • The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into
    15·1 answer
  • Which statement accurately describes the reactants of a reaction?
    7·1 answer
  • Evaluate Questions To narrow down the location for a new development, a construction company gets several plots of land assessed
    13·2 answers
  • Which of the following is true according the the Arrhenius theory of bases?
    11·1 answer
  • What happens at a convergent boundary?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!