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Valentin [98]
3 years ago
9

Which of the following pairs is mismatched? A. sodium hypochlorite-chlorine B. formalin-formaldehyde C. iodophor-iodine D. pheno

lics-peracetic acid E. benzalkonium chloride-quaternary ammonium compound
Chemistry
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

The mismatched pair is : D. phenolics-peracetic acid

Explanation:

A. sodium hypochlorite-chlorine: Correct pair

Sodium hypochlorite solution (NaOCl) is made from the reaction of chlorine and sodium hydroxide solution.

B. formalin-formaldehyde : Correct pair

The formalin solution is a 37% aqueous solution of formaldehyde.

C. iodophor-iodine : Correct pair

Iodophor, a combination of iodine and solubilizing agent. When diluted with water, iodophor releases free iodine.

D. phenolics-peracetic acid : wrong pair

Phenolics is a noun used for phenols, aromatic hydrocarbons with a hydroxyl group. Whereas, peracetic acid or peroxyacetic acid is an organic peroxide.

E. benzalkonium chloride-quaternary ammonium compound: Correct pair

Benzalkonium chloride is a quaternary ammonium organic salt, used as a cationic surfactant.

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\large \boxed{\text{b. 1.5 h}}

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\begin{array}{rcl}\ln \left (\dfrac{500}{31}\right) & = & k \times 6\\\\\ln 16.1 & = & 6k\\2.78& =& 6k\\k & = & \dfrac{2.78}{6}\\\\& = & 0.463 \text{ h}^{-1}\\\end{array}

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{\text{0.463  h}^{-1}} = \textbf{1.5 h}\\\\ \text{The half-life is $\large \boxed{\textbf{1.5 h}}$}

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