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3 years ago

I need help please please

Chemistry

1 answer:

inna [77]3 years ago

6 0

Answer:

B should be the answer, and ur low-key valid lol

Explanation:

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In an experiment, 34.8243g of copper (II) nitrate hydrate, Cu(NO3)2•zH2O was heated to a constant mass of 27.0351g. Calculate th

Leto [7]

Answer:

1) The mass of water lost = 7.7892 grams

2) Z = 3: Cu(NO3)2*3H2O

Explanation:

Step 1: Data given

Mass of copper (II) nitrate hydrate, Cu(NO3)2•zH2O = 34.8243 grams

Mass of substance after heating = 27.0351 grams

Molar mass of Cu(NO3)2 = 187.56 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: Calculate mass of water

The mass of water is the mass lost after heating.

Mass water = 34.8243 - 27.0351 = 7.7892 grams of water

Step 3: Calculate moles of Cu(NO3)2

Moles Cu(NO3)2 = Mass Cu(NO3)2 / Molar mass Cu(NO3)2

Moles Cu(NO3)2 = 27.0351 grams / 187.56 g/mol

Moles Cu(NO3)2 = 0.144 moles

Step 4: Calculate moles of H2O

Moles H2O = 7.7892 grams / 18.02 g/mol

Moles H2O = 0.432 moles

Step 5: Calculate Z

z = moles H2O / moles Cu(NO3)2

Z = 0.432/0.144

Z = 3

This means we have 3 water molecules in the formula. This makes the formula ofthe hydrate: Cu(NO3)2*3H2O

5 0

3 years ago

What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the

sweet [91]

Answer: The capillary rise(h) in the glass tube is = 0.009m

Explanation:

Using the equation

h = 2Tcosθ/rpg

Given

Contact angle, θ = Zero

h = height of the glass tube=?

T = surface tension = $0.032J/m^2$

r = radius of the tube = 0.1mm =0.0001m

p= density of ethanol = $0.71g/cm^3$

g= $9.8m/s^2$

h = $(2 * 0.032 * cos 0)/( 710*9.8*0.0001)$

h= 0.09m

Therefore the capillary rise in the tube is 0.09m

5 0

3 years ago

Perform the following operation and express the answer in scientific notation. 7.0x10^3x1.1x10^7

dimulka [17.4K]

Answer:

The answer is: $7.7\times10^{10}$

Explanation:

Scientific notation is of the kind: $a.bc\times10^{x}$

The given calculation:

$7.0\times10^{3}\times1.1\times10^{7}=(7\times1.1)\times10^{(3+7)}$

$=7.7\times10^{10}$

Therefore, the answer in scientific notation is: $7.7\times10^{10}$

4 0

3 years ago

Ewfewiofjwoiefjoiewjewijfwoiejfeo

Lostsunrise [7]

jsisoahxxhdjowoamxueoamsuid?

4 0

3 years ago

Hypothermic body temperature can range from 28.7 °C to 35.5 °C. What is this range in degrees Fahrenheit?

Amanda [17]

Solution:

To convert Celsius to Fahrenheit, the formula to be used is (C * 9/5) + 32

So in our given, 28.7 degrees Celsius:

Farenheit = (28.7 * 9/5) + 32
= 51.66 + 32
= 83.66 degrees Fahrenheit

Next, 35.5 degrees Celsius:
Farenheit = (35.5 * 9/5) + 32
= 63.9 + 32
= 95.9 degrees Fahrenheit

So in Fahrenheit, the range would be 83.66 – 95.9 degrees Fahrenheit.

5 0

3 years ago