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andrew-mc [135]
4 years ago
6

How many moles of water are in 100 grams

Chemistry
1 answer:
lina2011 [118]4 years ago
3 0

1 more of water requires 1 mole of hydrogen (H2) and 0.5 moles of oxygen (O2) . This requires 100/18 moles of hydrogen. As the molar mass of hydrogen is, 2 it requires 200/18= 100/9  g of hydrogen.

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I don’t know this question please help
vekshin1

Answer: A. is elliptical

B. IS inrregulur  C. spiral

Explanation: this should be it

3 0
3 years ago
3)<br> How many atoms are in 14 moles of cadmium?
andre [41]

Answer:

8.4322\times10^{24} atoms atoms are in 14 moles of cadmium.

Explanation:

Cadmium is a white and  silvery  metal  that is found in the curst of the earth.During the  production process of metals such as lead, copper, zinc, cadmium is extracted

Cadmium is present in some foods and is emitted when fossil fuels like as coal and oil is used, smoking cigarettes. It is used in craft glazes, metal batteries, and coatings.

We know that 1 mole of  Cadmium (Cd contains) 6.023*1023 atoms, which is Avogadro's number.

So in 14 Grams of Cadmium, the number of atoms present is,

=>14×number atoms present in one cadmium atom

=>14\times 6.023\times10^{23}

=>8.4322\times10^{24} atoms

5 0
4 years ago
Given that the ksp of aipo4 is 9.84 x 10-21 at 25°c, calculate the molar solubility of aiop4
svp [43]
AlPO4----> Al+3 + PO4-3

Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21

Ksp= (x) (x)= x^2
 
X^2= 9.84x10-21
 
x= 9.92 x 10^-11

The molar solubility is 9.92 x 10^-11
8 0
3 years ago
Read 2 more answers
Which characteristics can be inherited
andre [41]

Answer:

skin color, personality type, hair color/type, eye shape/type chin type, face shape etc.

Explanation:

hope this helps!

5 0
3 years ago
Read 2 more answers
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
4 years ago
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