Answer:
The time taken for the ball to fly up in the air and back down again is 3.058 seconds.
Explanation:
Since the ball ends up at the same vertical distance ( on the ground) as it was at the start of its motion, we can set the total displacement of the ball equal to 0.
Thus, this problem can be simply solved by the following equation of motion:
Here, s = total change in distance = 0 m
u = initial speed = 15 m/s
a = acceleration due to gravity = -9.81 m/s^2
t = time (to be found)
Substituting these values in the equation we get:
t = 3.058 seconds
So, the time taken for the ball to fly up in the air and back down again is 3.058 seconds.
Answer: The last part of the question has some details missing which is ; (Assume that the molecule's velocity is perpendicular to the two sides that it strikes.) molecule v=482 m/s molecule momentum=2.56 x 10^(-23)
Explanation:
- The momentum of the molecule is 2.56 x 10^(-23) .
- Particle hits the wall and bounces.
- Momentum is reversed. Change in momentum = impulse
- This is Force x time.
- Momentum change happens at a wall after each trip.
- time required = distance /speed
- Average force = impulse / time
- = 2 x 482 x 2.56 x 10^(-23) / (0.17 x 2)
- = 7.76 x 10^20N, is the average force the molecule exerts on one of the walls of the container.
We know, U = mgh
Substitute the known values,
19.6 = m * 9.8 * 8
m = 19.6 / 78.4
m = 1/4
In short, Your Answer would be 1/4 Kg
Hope this helps!
Answer:
I got the answer of yr question
but it is too long
brainly is not taking
True as the independent variable is over the dependent variable and controls it as the dependent relies on the independent.
