Answer:- 29.6 moles of carbon.
Solution:- We have been given with 3.7 moles of and asked to calculate the moles of C.
Looking at the formula of the compound, there are 8 carbons in it means 1 mol of he compound has 8 moles of C. So, if we multiply the given moles of the compound by 8 then we get the moles of C.
= 29.6 mol C
Hence. there are 29.6 moles of C in 3.7 moles of .
Explanation:
The given data is:
The half-life of gentamicin is 1.5 hrs.
The reaction follows first-order kinetics.
The initial concentration of the reactants is 8.4 x 10-5 M.
The concentration of reactant after 8 hrs can be calculated as shown below:
The formula of the half-life of the first-order reaction is:
Where k = rate constant
t1/2=half-life
So, the rate constant k value is:
The expression for the rate constant is :
Substitute the given values and the k value in this formula to get the concentration of the reactant after time 8 hrs is shown below:
Answer: The concentration of reactant remains after 8 hours is 2.09x10^-6M.