1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mekhanik [1.2K]
2 years ago
9

The properties of each state of a substance are due largely to the degree (amount) of intermolecular bonding. True False

Physics
1 answer:
marysya [2.9K]2 years ago
6 0

Answer:

true

Explanation:

You might be interested in
Help!!Help!!Help!!Help!!
DerKrebs [107]

Answer:

y=8

Explanation:

every time you multiply x by 3 you divide y by 3.

x=2, multiply it by 3: x=6

y=24, divide it by 3: y=8

8 0
2 years ago
Plz help due in 10 minutes will give brianlest to best answer
Ahat [919]

Answer:

Muscular Force = Uses when walking

The Force of wind = Force used to turn a windmill

Force of Gravity = Used to drag thing to the centre of the earth

Steam = Type of force used to operate machines

Work = Amount of force Times the distance moved

Foot - Pound = Moving one pound one foot

Newton meter = moving one newton one meter

Explanation:

4 0
3 years ago
Read 2 more answers
A charge of 63.0 nC is located at a distance of 3.40 cm from a charge of -47.0 nC. What are the x- and y-components of the elect
Serjik [45]

Answer:

Ep_x = 288.97*10^3\frac{N}{C}

Ep_y = 2770.6*10^3\frac{N}{C}

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/r²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

r: distance from charge q to point P in meters (m)

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

Equivalences

1nC= 10⁻⁹ C

1cm= 10⁻² m

Graphic attached

The attached graph shows the field due to the charges:

Ep₁: Total field at point P due to charge q₁. As the charge is positive ,the field leaves the charge.

Ep₂: Total field at point P due to charge q₂. As the charge is negative, the field enters the charge.

Known data

q₁ = 63 nC = 63×10⁻⁹ C

q₂ = -47 nC = -47×10⁻⁹ C

k = 8.99*10⁹ N×m²/C²

d₁ = 1.4cm = 1.4×10⁻² m

d₂ = 3.4cm = 3.4×10⁻² m

Calculation of r and β

r=\sqrt{d_1^2 + d_2^2} = \sqrt{(1.4*10^{-2})^2 + (3.4*10^{-2})^2} = 3.677*10^{-2}m

\beta = tan^{-1}(\frac{d_1}{d_2}) = tan^{-1}(\frac{1.4}{3.4}) = 22.38^o

Problem development

Ep: Total field at point P due to charges q₁ and q₂.

Ep = Ep_x i + Ep_y j

Ep₁ₓ = 0

Ep_{2x}=\frac{-k*q_2*Cos\beta}{r^2}=\frac{8.99*10^9*47*10^{-9}*Cos(22.38)}{(3.677*10^{-2})^2}=288.97*10^3\frac{N}{C}

Ep_{1y}=\frac{-k*q_1}{d_1^2}=\frac{8.99*10^9*63*10^{-9}}{(1.4*10^{-2})^2}=2889.6*10^3\frac{N}{C}

Ep_{2y}=\frac{-k*q_2*Sen\beta}{r^2}=\frac{-8.99*10^9*47*10^{-9}*Sen(22.38)}{(3.677*10^{-2})^2}=-119*10^3\frac{N}{C}

Calculation of the electric field components at point P

Ep_x = Ep_{1x} + Ep_{2x} = 0 + 288.97*10^3 = 288.97*10^3\frac{N}{C}

Ep_y = Ep_{1y} + Ep_{2y} = 2889.6*10^3 - 119*10^3 = 2770.6*10^3\frac{N}{C}

6 0
3 years ago
For each of the following decays or reactions, name at least. one conservation law that prevents it from occurring.(c) p → π⁺ +
Amanda [17]

(c)p→π⁺₊π⁺₊π

Baryon number is +1 on the left side of the equation, 0 on the

right side. Baryon number is not conserved.

<h3>How do you determine whether a baryon number is conserved?</h3>

  • According to the law of conservation of baryon number, the sum of the baryon numbers of all incoming particles equals the sum of the baryon numbers of all particles produced by the reaction. Energy, and so on, are conserved even if the incoming proton has sufficient energy and charge.
<h3>What is Baryon Number</h3>
  • In particle physics, the baryon number denotes which particles are baryons and which particles are not. Each baryon has a baryon number of 1, and each antibaryon has a baryon number of -1. Other non-baryonic particles have a baryon number of 0. Since there are exotic hadrons like pentaquarks and tetraquarks, there is a general definition of baryon number as:
  • B=1/3(n_{q} -n_q^{-} })
  • wheren_{q} represents the number of quarks and nq represents the number of antiquarks.

To learn more about Baryon Number refer to

brainly.com/question/10358797

#SPJ4

4 0
1 year ago
A car tyre is pumped to a pressure of 20000 Nm-2 in the morning when the temperature is 23 oC. Later in the day, the temperature
tekilochka [14]

Answer:

20743.24 Nm¯²

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P1) = 20000 Nm¯²

Initial temperature (T1) = 23 °C

Final temperature (T2) = 34 °C

Final pressure (P2) =?

Volume = constant

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T1) = 23 °C

Initial temperature (T1) = 23 °C + 273 = 296 K

Final temperature (T2) = 34 °C

Final temperature (T2) = 34 °C + 273 = 307 K

Finally, we shall determine the final (i.e the new) pressure of the tyre.

Initial pressure (P1) = 20000 Nm¯²

Initial temperature (T1) = 296 K

Final temperature (T2) = 307 K

Final pressure (P2) =?

Volume = constant

Since the volume is constant, the final (i.e the new) pressure of the tyre can be obtained by using the following formula:

P1/T1 = P2/T2

20000 / 296 = P2 /307

Cross multiply

296 × P2 = 20000 × 307

Divide both side by 296

P2 = (20000 × 307) /296

P2 = 20743.24 Nm¯²

Therefore, the new pressure of the tyre is 20743.24 Nm¯²

3 0
2 years ago
Other questions:
  • The unit light-year is a measure of
    9·2 answers
  • Much of the energy released in catabolic reactions is captured in ATP for use in other reactions. When the phosphate is transfer
    9·1 answer
  • Help it’s due tomorrow
    9·1 answer
  • Radio waves are readily diffracted around buildings, whereas light waves are negligibly diffracted around buildings. This is bec
    15·1 answer
  • If you're driving towards the sun late in the afternoon, you can reduce the glare from the road by wearing sunglasses that permi
    7·1 answer
  • A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp
    9·1 answer
  • Disease, pathogen , host and infectious in a sentence
    10·1 answer
  • An object
    11·1 answer
  • Need help asap please......
    8·2 answers
  • Which planet has a tilted axis of rotation similar to that of earth, which means it has seasons?.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!