The speed of the earth's surface located at 2/3 of the length of the arc between the pole which measure from the equator is 232.5 m/s.
Solution:
So the givens are, earth's radius = 6.37X10^6m, and the angular distance from the pole is 90 degrees. So 60 degrees is the 2/3.
r = 6.37x10^6 * cos(60) = 3.185x10^6m
since v = wr
v = 7.3x10^-5 * 3.185x10^6
v - 232.5 m/s
Answer:
The answer is below
Explanation:
a) The vertical displacement = Δy = 21.5 m - 1.5 m = 20 m
The horizontal displacement = Δx = 69 m wide
Using the formula:
Also:
b)The car is moving at a constant speed in the horizontal direction, hence the initial velocity = final velocity
If you look up "distance vs time graph" you can pull up images on google and check them out. That's what I did and on the x-axis (horizontal line) it said "time." I'd go with time.
Mechanical Energy transforms into Thermal due to the moving parts rubbing on eachother creating heat and friction.
I guess once you input the numbers into the correct places into the equation it would look like this :
PE = 50 * 9.8 * 5.0
PE = 2,450
