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4 years ago

I need help on 6 7,8 and 9

Physics

1 answer:

pantera1 [17]4 years ago

7 0

6. F- DNA
7. C
8. G
9. D
I believe these are correct, hope this helps.

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When a resistor is connected to a 12-V source, it draws a 185-mA current. The same resistor connected to a 90-V source draws a 1

german

Answer:

Explanation:

Ohm's law is define by the formula

V = IR where I is current in A, R is resistance in ohms

to calculate the resistance we use the formula above

I = 185 mA / 1000 = 0.185 A

case 1, R = V / I = 12 V / 0.185 A = 64.86 ohms

case 2, R = V / I = 90 / 1.25 A = 72 ohms

a) the resistor is not ohmic since there is no linear relationship between R and V ( as voltage increases, resistance ought to also increase)

b) rate of Joule heating in the case 1, P, power = IV = 0.185 A × 12 = 2.22 W

case 2, P = IV = 1.25 A × 90 V = 112.5 W

6 0

3 years ago

Read 2 more answers

As a healthcare professional. how do you plan. on maintaining. patient privacy

Romashka [77]

You dont share personal health information that has been de-identified so that it cannot link back to the patient .
You dont share any other PHI woth any other entity.

3 0

3 years ago

The Nardo ring is a circular test track for cars. It has a circumference of 12.5 km. Cars travel around the track at a constant

KIM [24]

Answer: 50 km, 0, 27.78 m/s

Explanation:

Given

Circumference of the track is $12.5\ km$

Speed of car is $100\ km/h$

Car drives for $30\ \text{minute}\ or\ 0.5\ hr$

(a)Distance traveled is

$\Rightarrow D=100\times 0.5\\\Rightarrow D=50\ km$

(b)displacement of the car

It can be observed that 12.5 is a multiple of 50, that is, 50 km can be interpreted as 4 complete rounds of the track.

Therefore, the displacement of the car is zero.

(c)To convert kmph to m/s, multiply the entity by $\frac{5}{18}$

$\Rightarrow 100\times \dfrac{5}{18}\\\\\Rightarrow 27.78\ m/s$

5 0

3 years ago

On land, coal is transported primarily by train. A typical large coal train may be about 1.5 km long and may consist of 120 cars

WINSTONCH [101]

Answer:

equivalent power = 6.60 × $10^{12}$ W

Explanation:

given data

coal train length = 1.5 km = 1500 m

contain = 120 cars

holding= 110 tonnes of coal each

train traveling speed = 100 km/h = 27.78 m/s

to find out

equivalent power in watts

solution

we take here energy produce by coal is 27 × $10^{6}$ J/kg

and here total coal = 120 × 110 × 10³ kg

sop here energy produce by total coal is

energy produce by total coal = 27 × $10^{6}$ × 120 × 110 × 10³

and time required to cross that distance is

time = $\frac{distance}{speed}$

time = $\frac{1500}{27.78}$

time = 53.99 sec

so here equivalent power will be

equivalent power = $\frac{energy}{time}$

equivalent power = $\frac{27*10^6*120*110*10^3}{53.99}$

equivalent power = 6.60 × $10^{12}$ W

6 0

3 years ago

What do you expect the enclosed current is for a bar magnet?

BartSMP [9]

The point P lies at a linear distance 1 m from the corner. Magnetic field due to current in wire Magnetic field due to current in wire. Applying Right hand thumb rule, the magnetic field at P is perpendicular to xy plane and into the plane of drawing (i.e. negative z-direction).

6 0

3 years ago