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3 years ago

2. Two trailers, X with mass 500 kg and Y with mass 2000 kg, are being pulled at the same

Physics

1 answer:

leva [86]3 years ago

4 0

Answer:C

Explanation:

let the speed be v for both mass x and mass y

mass(x)=500kg

mass(y)=2000kg

Kinetic energy(mass(x))=(500 x v^2)/2

Kinetic energy(mass(x))=250v^2

Kinetic energy(mass(y))=(2000xv^2)/2

Kinetic energy(mass(y))=1000v^2

Ratio of kinetic energy y to x =1000v^2:250v^2

=1000v^2 / 250v^2

=4/1=4:1

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2 years ago

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3 years ago

A rectangular loop of wire with width w = 5 cm, length L = 10cm, mass m = 40 g, and resistance R = 20 mΩ has an initial velocity

zhuklara [117]

Answer:

The loop penetrate 4 cm into the magnetic field.

Explanation:

Given that,

Width w= 5 cm

Length L= 10 cm

mass m = 40 g

Resistance R = 20 mΩ

Initial velocity = 1 m/s

Magnetic field = 2 T

We need to calculate the induced emf

Using formula of emf

$\epsilon=v_{0}Bw$

Put the value into the formula

$\epsilon =1\times2\times5\times10^{-2}$

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We need to calculate the current

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$i=\dfrac{\epsilon}{R}$

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We need to calculate the force

Using formula of force

$F=i(\vec{w}\times\vec{B})$

$F=iwB$

Put the value into the formula

$F=5\times5\times10^{-2}\times2$

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We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{F}{m}$

Put the value in to the formula

$a=\dfrac{0.5}{40\times10^{-3}}$

$a=12.5\ m/s^2$

We need to calculate the distance

Using equation of motion

$v^2=u^2+2as$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{0-1^2}{2\times(-12.5)}$

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3 years ago

What is the difference between constant and variable force ?

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3 years ago

A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a

Readme [11.4K]

Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

$H = 4.905 m$

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

$a = g = 9.81 m/s^2$

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

$v_f = 0$

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

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Part d)

at the maximum height position we know that the final speed will be zero

so we will have

$v_f^2 - v_i^2 = 2 a d$

here we have

$0 - (9.81^2) = 2(-9.81)H$

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3 years ago