All categories

3 years ago

How do I find the magnitude of the net force acting on the box

Physics

1 answer:

prohojiy [21]3 years ago

4 0

Answer:

20 N

Explanation:

Newton's second Law of motion law states that If there is a external force acting on an object. Then the rate of change of momentum of that object is directly proportional to the force acting on its.

the net force acting upon the object (F)
the mass of the object. (m)
V Final velocity of the object
U initial velocity of the object
mV -Final momentum of the object
mU - Initial momentum of the object

Due to momentum change of that object, momentum change. We can write the equation bellow this,

F = (mV-mU)/t

When m is constant we can write the above expression like this,

F = m (V-U)/t

There for

(V-U)/t = a ( Rate of change of velocity can be denoted as acceleration )

F = m× a

we can state this in mathematically,

a = F/m

in another representation

F = m*a

Net Force = mass*acceleration

= 10 * 2

= 20 N

object is subjected to a negative acceleration due to the friction.

You might be interested in

how does spatial pattern of heights illustrate the relationship between temperature density and the rate of vertical pressure ch

Anika [276]

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Generally, the relationship between temperature, density and rate of vertical pressure is given as;

$\rho = \frac{PM}{RT}$

$\frac{dP}{dz} = -\rho g\\\\$

where;

ρ is density
T is temperature
dP is rate of change of vertical pressure

Thus, from the formula above, we can conclude the following relationship between temperature, density and the rate of vertical pressure change in spatial pattern of heights.

The rate of change of vertical pressure is directly proportional to density and also directly proportional to temperature.

Learn more here:brainly.com/question/25395377

5 0

3 years ago

An injured monkey sits perched on a tree branch 9 m above the ground, while a wildlife veterinarian is kneeling down in the bush

Yakvenalex [24]

Answer:

The hunter should aim directly at the perched monkey because the tranquilizer dart will fall away from the line sight at the same rate that the monkey falls from its perch.

Tan theta = 9 / 90 = .1 so theta = 5.71 deg

The time for the monkey to reach the ground is

t = (2 h / g)^1/2 = (18 / 9.8)^1/2 = 1.36 sec

So the horizontal speed of the dart must be at least

Vx = 90 m / 1.36 sec = 66.4 m/s

Vx = V cos theta

V = 66.4 m/s / cos 5.71 = 66.7 m/s

7 0

3 years ago

A bullet with a mass of 5 gramsand speed of 560 m/sis fired horizontally atablock of wood with a mass of 2 kg. The block rests o

Anni [7]

Momentum is conserved if and only if sum of all forces which are exserted on system equals zero. In our situation there are only internal forces, so by Newton's third law their vector sum is 0.

So $mv=(m+M)v' \Leftrightarrow v'=\frac{mv}{m+M}$ .

Kinetic energy of system at first: $\frac{mv^2}{2}=784\;\textbf{J}$ . After: $\frac{(m+M)\frac{m^2v^2}{(m+M)^2} }{2}=\frac{m^2v^2}{2(m+M)}\approx 1,96\; \textbf{J}$ . The secret is that other energy is in work of deformation forces (they in turn heat a bullet and a block).

Answer is A)

5 0

3 years ago

The dragster has a mass of 1.3 Mg and a center of mass at G. A parachute is attached at C provides a horizontal braking force of

adell [148]

Answer:

The deceleration of the dragster upon releasing the parachute such that the wheels at B are on the verge of leaving the ground is 16.33 m/s²

Explanation:

The additional information to the question is embedded in the diagram attached below:

The height between the dragster and ground is considered to be 0.35 m since is not given ; thus in addition win 0.75 m between the dragster and the parachute; we have: (0.75 + 0.35) m = 1.1 m

Balancing the equilibrium about point A;

F(1.1) - mg (1.25) = $ma_a (0.35)$