Answer:
work done by electric field is 0.06 J
Explanation:
Given data:
Two point charge is 
0+1 charge positioned is (0 cm , 1 cm, 0.00 cm)
-1 charge positioned is (0 cm , -1 cm, 0.00 cm)
E = 3.0\times 10^6 N/C
From above information, the distance between given two charges d = 2 cm
then d = 0.02m
work needed is W = q E d

W = 0.06 J
Therefore work done by electric field is 0.06 J
Answer: C. Problem identification, solution design, implementation, evaluation.
Explanation:
Answer:
b
Explanation: because it says input file.read