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ad-work [718]
3 years ago
8

For questions A, B, C, and D. Determine if the Kinetic Energy will increase, decrease or stay the same based on the directions o

f their force and velocity vectors.

Physics
1 answer:
yuradex [85]3 years ago
8 0

Explanation:

KE = 1/2*m*v^2

mass won't change

but velocity is

A: the force is pushing against the direction of the object, so velocity is decreasing, so KE is decreasing

B: the F net line is pretty much straight up, which means there is no net force pushing to the left, but velocity is still increasing

Why? Because if you use the pythagorean theorem, the hypotenuse is always longer than the legs.

Note: velocity only ever stays the same if there is no net force (or 0 acceleration), so all four of these are either decreasing or increasing

C: there is a net force to the right, so velocity is increasing

D: There is a net force to the right but velocity is to the left, so velocity is decreasing

Hope I got these right

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A silver wire has a cross sectional area a = 2.0 mm2. a total of 9.4 × 1018 electrons pass through the wire in 3.0 s. the conduc
marta [7]
This problem uses the relationships among current I, current density J, and drift speed vd. We are given the total of electrons that pass through the wire in t = 3s and the area A, so we use the following equation to to find vd, from J and the known electron density n, so: 

v_{d} =  \frac{J}{n\left | q \right |}

<span>The current I is any motion of charge from one region to another, so this is given by:

</span>I = \frac{\Delta Q}{\Delta t} = \frac{9.4x1018electrons}{3s} = 3189.73(A)

The magnitude of the current density is:

J = \frac{I}{A} = \frac{3189.73}{2x10^{-6}} = 1594.86(A/m^{2})

Being:

A=2mm^{2} = 2x10^{-6}m^{2}
<span>
Finally, for the drift velocity magnitude vd, we find:

</span>v_{d} = \frac{1594.86}{5.8x1028\left |1.60x10^{-19}|\right } = 1.67x10^{18}(m/s)

Notice: The current I is very high for this wire. The given values of the variables are a little bit odd
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3 years ago
An object is accelerating if there is a change in speed and/or ________.
Alexxx [7]
A change in C. Direction.
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How do I solve the following problem?
lukranit [14]
Use the impulse-momentum theorem.

Ft = mv

Substitute your known values:

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Hope this helps!
7 0
3 years ago
The first artificial satellite to orbit the Earth was Sputnik I, launched October 4, 1957. The mass of Sputnik I was 83.5 kg, an
9966 [12]

Answer:

-4.941*10^8J.

Explanation:

To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.

By conservation of energy we know that,

\Delta U = \Delta_{perogee}-\Delta_{Apogee}

Where,

U= \frac{-GmM_e}{r}

Replacing

\Delta U = \frac{-GmM_e}{r_p}- \frac{-GmM_e}{r_a}

\Delta U = GmM_e (\frac{1}{r_A}-\frac{1}{r_p})

Our values are given by,

m = 85.5Kg

M_e = 5.97*10^{24}Kg

r_A = 7330Km

r_p = 6610Km

G = 6.67*10^{-11}Nm^2/Kg^2

Replacing at the equation,

\Delta U = (6.67*10^{-11})(85.5)(5.97*10^{24}) (\frac{1}{7330}-\frac{1}{6610})

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Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was -4.941*10^8J.

4 0
3 years ago
A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i
strojnjashka [21]

Answer:

The car exerts a force on the truck which  is c.)  6000 N.

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If the truck exerts a force of 6000 N on the car then according to Newton's Third Law of Motion that every action has an equal and opposite reaction we can say that the force exerted by the car on the truck is 6000 N.

The only reason the truck is able to move the car is because of the frictional forces. That is frictional force of the trucks tires on the surface of the road and the frictional forces of the cars tire on the surface of the road, and since these forces are not equal this therefore gives rise to motion.

7 0
3 years ago
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