<u>Project loon</u> balloons float in the stratosphere, twice as high as airplanes and the weather.
<h3>Project loon </h3>
Project loon was a project made to create wireless network by using high altitude balloons that floated in the stratosphere twice as high as an airplane could go, users where to connect to the balloon network via an antenna placed on their various buildings.
The project loon is still not a complete success and might be shut off anytime according to reports.
Hence we can conclude that project loon balloons float in the stratosphere twice as high as airplanes
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According to galilo in the absence of air resistance fraction then the body mass 60kg and 40kg will reach the earth surface at the same time....
Diffraction grating consists of a large number of fine slits.
Light gets split into different colors due to these slits of the diffraction grating.
Thus, diffraction grating produces a pattern of the coloured bands as each light wave passes through the slit at different speeds and different angles.
The speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
<h3>
What is Speed ?</h3>
Speed is a distance travelled by a body per time taken. It is a scalar quantity and it is measured in m/s
Given that at Initially stationary, a train has a constant acceleration of 0.9 m/s2.
(a) What is its speed after 21 s?
- Acceleration a = 0.9 m/s²
Using v = u + at
Substitute all the parameters into the equation
v = 0 + 0.9 x 21
v = 18.9 m/s
(b) What is the total time required for the train to reach a speed of 34 m/s?
Let first calculate for total distance by using
v² = u² + 2as
34² = 18.9² + 2 × 0.9 × S
1156 = 357.21 + 1.8S
1.8S = 1156 - 357.21
1.8S = 798.79
S = 798.79 / 1.8
S = 443.8 m/s
v = u + at
34 = 21 + 0.9t
0.9t = 34 - 21
0.9t = 13
t = 13/0.9
t = 14.44s
Therefore, its speed after 21 s is 18.9 m/s and the total time required for the train to reach a speed of 34 m/s is 14.4 s
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Explanation:
Given that,
Radius in which the satellite orbits, r = 6588 km
Solution,
The centripetal force acting on the satellite is balanced by the gravitational force acting between earth and the satellite. Its expression can be written by :
, M is the mass of earth
v = 7782.53 m/s
Let t is the time required to complete one orbit. It can be calculated as :
t = 5318.78 seconds
or
t = 1.47 hour
Therefore, this is the required solution.